Question

Solve the following system of equations. With multiplication 4x– 3y = -11 - 7x-8y= 6

Answer 1

4x - 3y = -11

-7x - 8y = 6

We need to cancel out one of the variables so let's multiply the first equation by 8 and the second by 3 and aim to cancel y.

32x - 24y = -88

-21x - 24y = 18

Now we subtract,

53x = -106

x = -2

3y = 4x + 11 = 4(-2) + 11 = 3

y = 1

Answer: (x,y)=(-2,1)

Check:

4(-2) -3(1) = -8 - 3 = -11, good

-7(-2) - 8(1) = 14 - 8 = 6, good