Solve the following system of equations. With multiplication
4x– 3y = -11
- 7x-8y= 6
1 answer:
4x - 3y = -11
-7x - 8y = 6
We need to cancel out one of the variables so let's multiply the first equation by 8 and the second by 3 and aim to cancel y.
32x - 24y = -88
-21x - 24y = 18
Now we subtract,
53x = -106
x = -2
3y = 4x + 11 = 4(-2) + 11 = 3
y = 1
Answer: (x,y)=(-2,1)
Check:
4(-2) -3(1) = -8 - 3 = -11, good
-7(-2) - 8(1) = 14 - 8 = 6, good
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Answer:
il faut passer les x de l'autre voter comme x=9+5=14 donc x=14 je pense que c'est ça mais je suis pas sûr et tu fait pareil pour l'autre
7.C I think is the answer
The answer to this question is
Both Parabolas open to the right, and x= 3y2 is wider than x= 5y2.
(APEX)
The original number is 72
(18+x)/6 = 1+14
1/6x + 3 = 1 + 14 (Distribute)
1/6x + 3 = (1+14) (Combine Like Terms)
1/6x + 3 = 15
- 3 = -3 (Subtract 3 From Both Sides)
1/6x = 12
(1/6x)*6 = 12 * 6 (Multiply Both Sides By 6)
x = 72
3.5 + 2 = 2x - 10
5.5 = 2x -10
+10 +10
—————————
15.5 = 2x
—— ——
2 2
7.75 = x
7.75 is the answer