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disa [49]
3 years ago
6

An equilateral triangle with one side 3.5 cm

Mathematics
1 answer:
RideAnS [48]3 years ago
7 0

if it's an equilateral all sides are same

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Simplify.<br> (-5)^5<br> ————<br> (-5)^-6<br><br> answer must be exponer
Rashid [163]
-5^11 you want to subtract -6 from 5 which become 5+6.
3 0
2 years ago
Write in simplest form 8/9_5/9
emmasim [6.3K]

Answer: the answer is 1/3

8 0
4 years ago
A factory is to be built on a lot measuring 210 ft by 280 ft. A local building code specifies that a lawn of uniform width and e
Tresset [83]

Answer:

Width of lawn = 35 ft

Dimensions of factory = length: 210 ft, width: 140 ft

Step-by-step explanation:

The total area of the lot can be calculated as:

A_{lot} = 210 * 280\\A_{lot} = 58800 ft^{2}

Since, the area of factory should be equal to area of lawn:

A_{lot} = A_{factory} + A_{lawn}\\58800 = 2 A_{factory or lawn}\\\\A_{factory or lawn} = \frac{58800}{2}\\A_{factory or lawn} = 29400 ft^{2}

Now, let 'x' be the width of lawn, the dimensions of factory can be written as:

(210-2x)\\(280-2x)\\

Since, area is equal to length x width:

(210-2x)*(280-2x) = 29400\\Simplifying:\\210*280 - 210*2x - 2x*280 + 4x^{2} = 29400\\58800 - 420x - 560x +4x^{2} = 29400\\4x^{2}  - 980x +58800 = 29400\\4x^{2} - 980x + 29400 = 0\\

Divide whole equation by 4,

x^{2} - 245 + 7350 = 0\\

Solving above quadratic equation, we get,

x = 210\\x = 35\\

x = 35 seems realistic width of the lawn.

Now, finding the dimension of factory:

(210-2x) = 210 - 2(35) = 140 ft\\(280-2x) = 280 - 2(35) = 210ft

We can also reconfirm the area of factory by multiplying the above two lengths:

140 * 210 = 29400 ft

8 0
3 years ago
Prime factorization of 48?
VikaD [51]

Answer: 2 x 2 x 2 x 2 x 3

Step-by-step explanation: To find the prime factorization of 48, first create a factor tree with two branches.

When a number is even, it's often easiest to start by dividing by 2 to find factors.

Since 48 ÷ 2 . is 24, we know that 2 and 24 are factors of 48 so we write 2 and 24 at the bottom of the branches.

Next, we circle any prime factors in the factor tree. Since 2 is classified as a prime number, we circle 2 but since 24 is not a prime number, we draw two new branches.

Since 24 ÷ 2 is 12, we know that 2 and 12 are factors of 24 so we write 2 and 12 at the bottom of the branches.

Next, we circle any prime factors in the factor tree. Since 2 is classified as a prime number, we circle 2. Since 12 is not a prime number, we draw two new branches.

Since 12 ÷ 2 is 6, we know that 2 and 6 are factors of 12. This means that we write 2 and 6 at the bottom of the branches. Next, we circle any prime factors in the factor tree. Since 2 is a prime number, we circle 2 but draw two new branches coming down from 6 because it's not prime.

Since 6 ÷ 2 is 3, we know that 2 and 3 are factors of 6 so we write 2 and 3 at the bottom of the branches. Next, we circle any prime factors in the factor tree. Since both 2 and 3 are prime meaning that the only factors they have are 1 and the number itself, we circle both 2 and 3.

Since we have circles at the bottom of all of the branches, we are finished.

So the prime factorization of 48 is 2 × 2 × 2 × 2 × 3.

Notice that the factor 2 is repeated 4 times. In this case, we can rewrite the prime factorization of 48 using exponents as 2^{4} x 3

5 0
3 years ago
Among the thirty largest U.S. cities, the mean one-way commute time to work is 25.8 minutes. The longest one-way travel time is
Dafna11 [192]

Answer:

A. 0.9015

B. 0.1658

C. 0.0132

Step-by-step explanation:

Given

Mean, μ of commuting time in New York is 39.7 minutes

Standard Deviation, σ = 7.5 minutes

Let x represent the commute time

For Normal Distribution, z = (x - μ) /σ

A. x is less than 30 minutes

P(x<30) = P(x - μ < 30 - μ)

P(x<30) = P((x - μ)/ σ < (30 - μ)/ σ)

P(x<30) = P(z < (30 - μ)/ σ)

P(x<30) = P(z < (30 - 39.7) / 7.5)

P(x<30) = P(z < (-9.7/7.5)

P(x<30) = P(z < -1.29)

P(x<30) = P(z > 1.29)

P(x<30) = 0.9015 -------- From z table

B. x is between 30 and 35

P(30>x<35) = P(30 -μ > x - μ < 35 - μ)

P(30>x<35) = P((30 -μ)/σ < (x - μ)/σ < (35 - μ) / σ)

P(30>x<35) = P((30 -μ)/σ < z < (35 - μ) / σ)

P(30>x<35) = P((30 -39.7)/7.5 < z < (35 - 39.7) / 7.5)

P(30>x<35) = P(-9.7/7.5 < z < -4.7/7.5)

P(30>x<35) = P(-1.29 < z < -0.63)

There are two points on the same side here; we calculate both probabilities and subtract to give

P(30>x<35) = P(-1.29 < z < 0) - P(0 < z < -0.63)

P(30>x<35) = P(0 < z < 1.29) - P(0 < z < 0.63)

P(30 > x < 35) = 0.9015 - 0.7357

P(30 > x < 35) = 0.1658

C. x is between 30 and 50

P(30>x<50) = P(30 -μ > x - μ < 50 - μ)

P(30>x<50) = P((30 -μ)/σ < (x - μ)/σ < (50 - μ) / σ)

P(30>x<50) = P((30 -μ)/σ < z < (50 - μ) / σ)

P(30>x<50) = P((30 -39.7)/7.5 < z < (50 - 39.7) / 7.5)

P(30>x<50) = P(-9.7/7.5 < z < 10.3/7.5)

P(30>x<50) = P(-1.29 < z < 1.37)

There are two points on different sides here; calculate both probabilities and add to give

P(30>x<50) = P(-1.29 < z < 0) + P(0 < z < 1.37)

P(30>x<50) = -P(0 < z < 1.29) + P(0 < z < 1.37)

P(30 > x < 50) = -0.9015 + 0.9147

P(30 > x < 50) = 0.0132

8 0
3 years ago
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