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Katen [24]
3 years ago
6

GET THIS RIGHT AND YOU'LL GET (100) POINTS

Mathematics
2 answers:
riadik2000 [5.3K]3 years ago
6 0
10 13 3 12 2 Is the right answer
Leno4ka [110]3 years ago
3 0

Answer:

10 13 3 12 2

Step-by-step explanation:

there is no true pattern, the numbers written out in letters are listed alphabetically in order

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Graph the data from the tables onto the following graph. Note that for both tables, the values in the first column must be plott
DENIUS [597]

Graphs are used to visualize the set of data on a table or functions and equations

<h3>How to graph the table?</h3>

The table is not given.

So, I will make use of the following table to plot the graph

x     y

1       2

2      4

3      6

4      8

5     10

To plot the table on a graph, we place the x values on the x-axis, and the y values on the y-axis

See attachment for the graph of the table

Read more about graphs and tables at:

brainly.com/question/14323743

5 0
3 years ago
when a stone falls freely, the time taken to hit the ground varies as the square root of the distance fallen. If it takes four s
Eva8 [605]

Answer:

The stone would take approximately 10.107 seconds to fall 500 meters.

Step-by-step explanation:

According to the statement of the problem, the following relationship of direct proportionality is built:

t \propto y^{1/2}

t = k\cdot t^{1/2}

Where:

t - Time spent by the stone, measured in seconds.

y - Height change experimented by the stone, measured in meters.

k - Proportionality constant, measured in \frac{s}{m^{1/2}}.

First, the proportionality constant is determined by clearing the respective variable and replacing all known variables:

k = \frac{t}{y^{1/2}}

If t = 4\,s and y=78.4\,m, then:

k = \frac{4\,s}{(78.4\,m)^{1/2}}

k \approx 0.452\,\frac{s}{m^{1/2}}

Then, the expression is t = 0.452\cdot y^{1/2}. Finally, if y = 500\,m, then the time is:

t = 0.452\cdot (500\,m)^{1/2}

t \approx 10.107\,s

The stone would take approximately 10.107 seconds to fall 500 meters.

4 0
3 years ago
If there were 49 cars in a line that stretched 528 feet, what is the average car length? assume that the cars are lined up bumpe
lakkis [162]

If there were 49 cars in a line that stretched 528 feet, what is the average car length? assume that the cars are lined up bumper-to-bumper

Answer: We are given there are 49 cars

Also these 49 cars are in a line stretched 528 feet.

Now the average length of the car is:

Average length = \frac{(length-covered-by-49-cars)}{Number-of-cars}

                          =\frac{528}{49}=10.78

Therefore, the average length of car is 10.78 feet

                 

6 0
3 years ago
For the function h(x) defined below, find function f(x) and g(x) so that h(x)=(f^ g)(x) . h(x) = ((x + 2)/x) ^ 3
dem82 [27]

Answer:

Step-by-step explanation:

c

4 0
3 years ago
My last problem and I'm stuck please help!!​
WITCHER [35]
Answer is C= -125,125
4 0
3 years ago
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