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4 years ago

May someone help me with this quick math problem

Mathematics

1 answer:

vekshin14 years ago

8 0

Hello,

The correct answer is D) 2

Median: To find the Median, place the numbers you are given in value order and find the middle number. Example: find the Median of {13, 23, 11, 16, 15, 10, 26}. Put them in order: {10, 11, 13, 15, 16, 23, 26} The middle number is 15, so the median is 15. (If there are two middle numbers, you average them.)

The median number of trips taken to the food store in 1 week is 2.

4 - 2 = 2

Hope this helps!!!! :)

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I know that it's 9:41 but i need help!

lesya692 [45]

Answer:

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Step-by-step explanation:

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3 years ago

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3 years ago

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Find the inverse of the function f(x)=0.6(x/5+1.3).then graph the function in the inverse. Express any fractions decimals rounde

Oksanka [162]

To find the inverse of a function, switch x and y and solve for y. In this case y=0.6(x/5+1.3) turns into x=0.6(y/5+1.3).
x/0.6=y/5+1.3 (I divided both sides by 0.6)
x/0.6-1.3=y/5 (I subtracted 1.3 from both sides)
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8 0

3 years ago

Ten college students were randomly selected. Their grade point averages (GPAs) when they entered the program were between 3.5 a

solong [7]

Answer:

The 95% confidence interval for the true slope is (0.03985, 0.14206).

Step-by-step explanation:

For the regression equation:

$\hat y=\alpha +\hat \beta x$

The (1 - <em>α</em>)% confidence interval for the regression coefficient or slope $(\hat \beta )$ is:

$Ci=\hat \beta \pm t_{\alpha/2, (n-2)}\times SE(\hat \beta )$

The regression equation for current GPA (Y) of students based on their GPA's when entering the program (X) is:

$\hat Y=3.584756+0.090953 X$

The summary of the regression analysis is:

Predictor Coefficient SE t-stat p-value

Constant 3.584756 0.078183 45.85075 5.66 x 10⁻¹¹

Entering GPA 0.090953 0.022162 4.103932 0.003419

The regression coefficient and standard error are:

$\hat \beta = 0.090953\\SE (\hat \beta)=0.022162$

The critical value of <em>t</em> for 95% confidence level and 8 degrees of freedom is:

$t_{\alpha/2, n-2}=t_{0.05/2, 10-2}=t_{0.025, 8}=2.306$

Compute the 95% confidence interval for $(\hat \beta )$ as follows:

$CI=\hat \beta \pm t_{\alpha/2, (n-2)}\times SE(\hat \beta )\\=0.090953\pm 2.306\times 0.022162\\=0.090953\pm 0.051105572\\=(0.039847428, 0.142058572)\\\approx (0.03985, 0.14206)$

Thus, the 95% confidence interval for the true slope is (0.03985, 0.14206).

6 0

3 years ago

Which expression has the same value as 5(4x+4)

aev [14]

Answer: 20x + 20

Step-by-step explanation: In this problem, the 5 "distributes" through the parentheses, multiplying by each of the terms inside.

So we have 5(4x) + 5(4) which simplifies to 20x + 20.

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3 years ago