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sergey [27]
3 years ago
15

Multiply and simplify the following products. V stands for radical.

Mathematics
1 answer:
Reptile [31]3 years ago
5 0

Answer:

(1) 9

(2) \sqrt{6}

(3) 6(\sqrt{6})

Step-by-step explanation:

From the question,

(1) (\sqrt{9})²

    Applyin the law of multiplication of surds

   (\sqrt{9})²  = (

(2)  (\sqrt{2})× (\sqrt{3}) =

   Also applying the the law of multiplication of surd

   (\sqrt{2\\})×(\sqrt{3}) =  (\sqrt{6}) ( This is an irational answer)

   ∴ (\sqrt{2})×(\sqrt{3})  = \sqrt{6}

 (3) 2(\sqrt{2})×3(\sqrt{3})

     Also applying the law of multiplication of surds i.e Multiply surds to     surds and whole number to whole number

     = 2×3×(\sqrt{2})×(\sqrt{3})

       6×(\sqrt{6}) = 6(

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PLEASE HELP! Solve each of the following by using the general quadratic formula.
Archy [21]

Using the quadratic formula, the solutions are:

a) x = \frac{3 \pm \sqrt{41}}{4}

b) x = 1 \pm 2i

<h3>What is a quadratic function?</h3>

A quadratic function is given according to the following rule:

y = ax^2 + bx + c

The solutions are:

x_1 = \frac{-b + \sqrt{\Delta}}{2a}

x_2 = \frac{-b - \sqrt{\Delta}}{2a}

In which:

\Delta = b^2 - 4ac

Item a:

The coefficients are a = 2, b = -3, c = -4, hence:

  • \Delta = (-3)^2 - 4(2)(-4) = 41
  • x_1 = \frac{3 + \sqrt{41}}{4}
  • x_2 = \frac{3 - \sqrt{41}}{4}

Item b:

The coefficients are a = 1, b = 2, c = 2, hence:

  • \Delta = (2)^2 - 4(1)(2) = -4
  • x_1 = \frac{2 + \sqrt{-4}}{2} = 1 + 2i
  • x_2 = \frac{2 - \sqrt{-4}}{2} = 1 - 2i

More can be learned about quadratic equations at brainly.com/question/24737967

#SPJ1

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