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exis [7]
3 years ago
12

What's the answer??? Help me asap

Mathematics
2 answers:
Angelina_Jolie [31]3 years ago
6 0
I know b, d, and f for sure. Defiantly not c. 
Nina [5.8K]3 years ago
3 0
B, and E are my best guess
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The area of the shape shown below?
krek1111 [17]

Answer:

The answer is 12 units^2.

#Hope it helps uh.........

3 0
3 years ago
In an orchestra the ratio of trombones to violas is 1 to 3.
ICE Princess25 [194]
The proportion would be 1/3 and x/9. Cross multiplication creates 3x=9. Divide both sided by three, and there are 3 trombones in the orchestra.
5 0
3 years ago
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Can the set of lengths be the side lengths of a right triangle?
andreyandreev [35.5K]

Answer:

B. No.

Step-by-step explanation:

We have been given 3 side lengths 7 ft, 12 ft, 17 ft. We are asked to determine, whether the given set of lengths can form a right triangle or not.

We will use Pythagoras theorem to solve our given problem, which states that the square of hypotenuse of a right triangle is equal to the sum of squares of two legs of right triangle.

17^2=12^2+7^2

289=144+49

289>193

Since the sum of  squares of both legs is less than square of hypotenuse, therefore, the given set of lengths can not be the side lengths of a right triangle.

4 0
3 years ago
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Find the tangent of angle Θ in the triangle below.
Rina8888 [55]

Answer: \frac{\sqrt{65}}{4}

Step-by-step explanation:

By the Pythagorean theorem, the unknown side has length

\sqrt{9^{2}-4^{2}}=\sqrt{65}

Therefore,

\tan \theta=\boxed{\frac{\sqrt{65}}{4}}

4 0
2 years ago
The given line segment has a midpoint at (3, 1).
Katena32 [7]

Answer:

y=\frac{1}{3}x

Step-by-step explanation:

The given line segment has a midpoint at (3, 1) and goes through (2, 4), (3, 1), and (4, -2). We can use any two of the three points to calculate the equation of the line. Let us use the points (2, 4) and (4, -2)

Therefore the line goes through (2, 4) and (4, -2). The equation of a line passing through (x_1,y_1)\ and\ (x_2,y_2) is:

\frac{y-y_1}{x-x_1}=\frac{y_2-y_1}{x_2-x_1}.

Therefore the line passing through (2, 4) and (4, -2) has an equation:

\frac{y-y_1}{x-x_1}=\frac{y_2-y_1}{x_2-x_1}\\\frac{y-4}{x-2}=\frac{-2-4}{4-2}\\\frac{y-4}{x-2}=\frac{-6}{2}\\y-4=x-2(-3)\\y-4=-3x+6\\y=-3x+10

Comparing with the general equation of line: y = mx + c, the slope (m) = -3 and the intercept on the y axis (c) = 10

Two lines are said to be perpendicular if the product of their slope is -1. If the slope of line one is m1 and the slope of line 2 = m2, then the two lines are perpendicular if:

m_1m_2=-1.

Therefore The slope (m2) of the perpendicular bisector of y = -3x + 10 is:

m_1m_2=-1\\-3m_2=-1\\m_2=\frac{1}{3}

Since it is the  perpendicular bisector of the given line segment, it passes through the midpoint (3, 1). The equation of the perpendicular bisector is:

\frac{y-y_1}{x-x_1}=m\\\frac{y-1}{x-3}=\frac{1}{3}\\ y-1= \frac{1}{3}(x-3)\\ y-1=\frac{1}{3}x-1\\y=\frac{1}{3}x

the equation, in slope-intercept form, of the perpendicular bisector of the given line segment is y=\frac{1}{3}x

7 0
3 years ago
Read 2 more answers
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