Tenemos un problema algebraico.
Veremos que Martha saco 98 fotos
La información que tenemos es:
Martha y Raúl tomaron un total de 175 fotos.
Raúl tomo 77.
Para encontrar el número de fotos que saco Martha, simplemente debemos calcular la diferencia entre la cantidad total de fotos que sacaron y las que sabemos que saco Raúl:
175 - 77 = 98
Podemos así concluir que Martha saco 98 fotos
Si quieres aprender más, puedes leer:
brainly.com/question/24504419
<h3>
Answer:</h3>
<em>None of the above</em>. All the answers refer to <em>price</em>. The given equation refers to <em>value</em>. We imagine price may stay the same or actually increase year-to-year. The problem statement gives insufficient information to conclude anything about <em>price</em>.
Math is about attention to detail. The equation tells you ...
... The <em>value</em> of the boat decreases by 12% every year.
<h3>
Step-by-step explanation:</h3>
The value of the boat is multiplied by 0.88 each time X increases by 1. That means the value is 88% of what it was the year before, <em>a decrease of 12%</em>.
Answer:
Continuous graphs have all real numbers
Discrete graphs have whole numbers
Step-by-step explanation:
Answer:
The value of the parameter is λ is 0.03692
Step-by-step explanation:
Consider the provided function.
for −∞ < x < ∞.
It is given that standard deviation is given as 38.3 km.
Now we need to calculate the value of parameter λ.
The general formula for the probability density function of the double exponential distribution is: 
Where μ is the location parameter and β is the scale parameter.
Compare the provided equation with the above formula we get.
and μ = 0.
Standard deviation = √2β
Now substitute the value of β in .
Hence, the value of the parameter is λ is 0.03692
Answer:
{-3, 2}U{2, 5}
Step-by-step explanation:
For an equation to be negative, it would need to be in a negative range (below the x-axis or the coordinates are negative y-values). Therefore, we can examine this question and see that the graph is negative when the function crosses the x-axis at -3 and it remains negative until you reach 2 on the x-axis.
Therefore, the first set of negative values is (-3, 2).
Secondly, applying the same logic as before, the function decreases at 2 and then touches the x-axis again at 5. Therefore, the second negative value would be (2, 5).
The negative values are {-3, 2}U{2, 5}.
