bolts of length more than 
, and less than 
will be destroyed
= 13.20 cm and 12.80 cm
<u>Step-by-step explanation:</u>
Here we have , A manufacturer of bolts has a quality-control policy that requires it to destroy any bolts that are more than 2 standard deviations from the mean. The quality-control engineer knows that the bolts coming off the assembly line have mean length of 13 cm with a standard deviation of 0.10 cm. We need to find For what lengths will a bolt be destroyed .Let's find out:
A manufacturer of bolts has a quality control policy that requires it destroy any bolts that are more than 2 standard deviations from the mean.
mean length= 
standard deviation= 
2 standard deviation from mean= 
Therefore, bolts of length more than , and less than will be destroyed
= 13.20 cm and 12.80 cm
Therefore 0.28 is greater.
Hope this helps!
∠FEG is an exterior angle.
An exterior angle of a triangle is equal to the sum of the opposite interior angles, so
2x + x = x + 40
3x = x + 40
3x - x = 40
2x = 40
x = 20
m∠FEG = x+40 = 20+40 = 60°
Answer:
The answer is 30 or 7.5
Step-by-step explanation:
There are two answers because you haven't specified whether the 15 corresponds with the 5 or the 10 so I did both.
If the 15 corresponds with the 5 then the scale factor is 3 because 15 ÷ 5 = 3. To find the unknown amount you have to multiply the 10 by 3 to get 30.
If the 15 corresponds with the 10 then the scale factor is 1.5 because 15 ÷ 10 = 1.5. To find the unknown amount you have to multiply the 5 by 1.5 to get 7.5.
So depending on whether the 15 corresponds to the dimension 5 or 10 you have two answer, you can use the one that applies to you.
This is a problem of
Arithmetic that is a branch of mathematics that consists of the study of numbers. Its main goal is the study of the traditional operations on them just as: <em>addition, subtraction, multiplication and</em><span><em> division</em>. </span>There is an order of operation to solve problems in arithmetic that is the way you choose to simplify expressions. This order is like this:
1. First. Solve Parentheses.
2. Second. Solve Exponents (and root).
3. Third. Solve Multiplication and Division
3. Fourth. Solve addition and subtraction.
So let's apply these concepts to our problem:
We don't have parentheses, so let's apply
second step:
Applying
third step:
Finally, applying
fourth step, the result is:
