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Wittaler [7]
3 years ago
11

What is the area of the hexagon? 60 m 2 80 m 2 100 m 2 120 m 2

Mathematics
1 answer:
larisa86 [58]3 years ago
6 0

We can think of this hexagon as two trapezoids with the same area. Each has height 5 and bases 6 and 10.

A = 2 \left(\frac 1 2 (b_1 + b_2) h \right) = h(b_1 + b_2)

A = 5(6 + 10) = 80

Answer: 80 square meters, second choice

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user100 [1]

Answer:

answer: Volume sa Cellphone:)

8 0
3 years ago
How many 1/3 inch cubes does it take to fill a box with width 2 213 inches, length 3 1/3
MAVERICK [17]

Answer:

560 cubes

Step-by-step explanation:

Is 2 213 supposed to read 2 1/3? First calculate the volume of the box

V_box = 8/3 * 10/3 * 7/3 = 560/27 cubic inches

Now calculate the volume of your 1/3 inch cube:

V_cube = 1/3 * 1/3 * 1/3 = 1/27 cubic inches

Now divide the V_box by V_cube:

Number of boxes = (560/27) / (1/27) = (560/27) * (27/1) = 560 cubes

8 0
3 years ago
PLZ HELP ME ASAP PLZ PLZ PLZ!!!!! I NEED LOTS OF HELP!!! I USED 40 POINTS
cupoosta [38]
First, some defintions
reciprocals are like a/b and b/a or 5/1 and 1/5

remember, \frac{\frac{a}{b}}{\frac{c}{d}}=(\frac{a}{b})(\frac{d}{c})=\frac{ad}{bc}

john's fraction is reciprocal of sarah's
john=a/b
sarah=b/a

david multiplies his by sarah and gets 12/35
(b/a)(david)=12/35

multplies his number by john and gets 12/35
(a/b)(david)=15/7

hmmm

(b/a)(david)=12/35 and
(a/b)(david)=15/7

if we divide them then we do
\frac{(\frac{b}{a})(david)}{(\frac{a}{b})(david)}=\frac{\frac{12}{35}}{\frac{15}{7}}=
\frac{\frac{b}{a}}{\frac{a}{b}}=\frac{\frac{12}{35}}{\frac{15}{7}}=
(\frac{b}{a})(\frac{b}{a})=(\frac{12}{35})(\frac{7}{15})=
\frac{b^2}{a^2}=\frac{84}{525}=
\frac{b^2}{a^2}=\frac{4}{25}
square root both sides
\frac{b}{a}=\frac{2}{5}

therefor
b=2 and a=5

john's number is a/b=5/2
sarah's number is 2/5

david, hmm

sarah times david=12/35
2/5 times david=12/35
times both sides by 5/2
david=60/70
david=6/7

check other

john times david=15/7
5/2 times 6/7=15/7
30/14=15/7
15/7=15/7
true





sarah's favorite number is 2/5
john's favorite number is 5/2
david's favorite number is 6/7
6 0
3 years ago
PLS HELP HURRY NEED rigGHT ANWSER
Alex787 [66]

Answer:

(3, -4)

Step-by-step explanation:

Lines are intersecting at points (3, -4).

So, the solution of the given system of equations is (3, -4).

Hope it helps you in your learning process.

4 0
2 years ago
The length of each side of a regular pentagon is increased by 8 inches, so the perimeter is now 65 inches. What is the original
evablogger [386]

<em>Here</em> as the <em>Pentagon</em> is <em>regular</em> so it's <em>all sides</em> will be of <em>equal length</em> . And if we assume It's each side be<em> </em><em><u>s</u></em> , then it's perimeter is going to be <em>(s+s+s+s+s) = </em><em><u>5s</u></em>.And as here , each <em>side</em> is increased by <em>8 inches</em> and then it's perimeter is <em>65 inches</em> , so we got that it's side after increament is<em> (s+8) inches</em> and original length is <em>s inches </em>. And if it's each side is <em>(s+8) inches</em> , so it's perimeter will be <em>5(s+8)</em> and as it's equal to <em>65 inches</em> . So , <em><u>5(s+8) = 65</u></em>

{:\implies \quad \sf 5(s+8)=65}

{:\implies \quad \sf 5s+5\times 8=65}

{:\implies \quad \sf 5s+40=65}

{:\implies \quad \sf 5s=65-40}

{:\implies \quad \sf 5s=25}

{:\implies \quad \sf s=\dfrac{25}{5}=5}

{:\implies \quad \bf \therefore \quad \underline{\underline{s=5\:\: Inches}}}

As we assumed the original side to be <em><u>s</u></em> .

<em>Hence, the original side's length 5 inches </em>

8 0
2 years ago
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