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2 years ago

What is the area of the hexagon? 60 m 2 80 m 2 100 m 2 120 m 2

Mathematics

1 answer:

larisa86 [58]2 years ago

6 0

We can think of this hexagon as two trapezoids with the same area. Each has height 5 and bases 6 and 10.

$A = 2 \left(\frac 1 2 (b_1 + b_2) h \right) = h(b_1 + b_2)$

$A = 5(6 + 10) = 80$

Answer: 80 square meters, second choice

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Find the angle between u = (-2,-5) and v = (5,2)

OleMash [197]

The angle between u = (-2,-5) and v = (5,2) is 134 degrees approximately.

Solution:

Given, two vectors are u = (-2, -5) and v = (5, 2)

We have to find the angle between two vectors.

We know that,

$a. b=\|a\| .\|b\| \times \cos \theta$

where $\theta$ is angle between vectors a and b

$\text { Now vectors are }(-2 \vec{\imath}-5 \vec{\jmath}) \text { and }(5 \vec{\imath}+2 \vec{\jmath})$

$(-2 \vec{\imath}-5 \vec{\jmath}) \cdot(5 \vec{\imath}+2 \vec{\jmath})=\sqrt{(-2)^{2}+(-5)^{2}} \times \sqrt{5^{2}+2^{2}} \times \cos \theta$

$\text { since }\|a\|=\sqrt{x^{2}+y^{2}} \text { for } a=x \vec{\imath}+y \vec{\jmath}$

$\begin{array}{l}{-10-10=\sqrt{29} \times \sqrt{29} \times \cos \theta} \\\\ {-20=29 \times \cos \theta} \\\\ {\cos \theta=\frac{-20}{29}} \\\\ {\theta=\cos ^{-1} \frac{-20}{29}} \\\\ {\theta=133.60}\end{array}$

Hence, the angle between given two vectors is 134 degrees approximately.

3 0

3 years ago

Fill in each of the missing parts of the hierarchy of the quadrilaterals. Include the properties of each of the figures.

Ber [7]

Answer:

I just edited the file you linked.

Download pdf

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1 year ago

Which symbol makes a true statement? –2.75 ? –3 A. = B. > C.

Iteru [2.4K]

–2.75 > –3

answer is B. >

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2 years ago

The sum of 3x^2 -8x -2 and 4x -2 is?

Lady_Fox [76]

Answer:

3x^2−4x−4

Step-by-step explanation:

3x^2−8x−2+4x−2

=3x^2+−8x+−2+4x+−2

3x^2+−8x+−2+4x+−2

=(3x^2)+(−8x+4x)+(−2+−2)

=3x^2+−4x+−4

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2 years ago

Read 2 more answers

35,000,000 what is the order of magnitude of this number

uysha [10]

The anwser is 7 your welcome!

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2 years ago