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Luden [163]
3 years ago
8

Find m A. 20 B. 40 C. 60 D.120

Mathematics
2 answers:
KonstantinChe [14]3 years ago
7 0
The answer is C. 

 I only know this because it is an acute angle so "D" is wrong. It is also too wide to be "A" or "B" so the only of that is left is "C". through process of elimination.
Hatshy [7]3 years ago
4 0
∠FEG is an exterior angle.
An exterior angle of a triangle is equal to the sum of the opposite interior angles, so

2x + x = x + 40
3x = x + 40
3x - x = 40
2x = 40
x = 20

m∠FEG = x+40 = 20+40 = 60°
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Triangle JKL has vertices J(2,5), K(1,1), and L(5,2). Triangle QNP has vertices Q(-4,4), N(-3,0), and P(-7,1). Is (triangle)JKL
Tems11 [23]

Answer:

Yes they are

Step-by-step explanation:

In the triangle JKL, the sides can be calculated as following:

  • J(2;5); K(1;1)

             => JK = \sqrt{(1-2)^{2} + (1-5)^{2}  } = \sqrt{(-1)^{2}+(-4)^{2}  } = \sqrt{1+16}=\sqrt{17}

  • J(2;5); L(5;2)

             => JL = \sqrt{(5-2)^{2} + (2-5)^{2}  } = \sqrt{3^{2}+(-3)^{2}  } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}

  • K(1;1); L(5;2)

             =>  KL = \sqrt{(5-1)^{2} + (2-1)^{2}  } = \sqrt{4^{2}+1^{2}  } = \sqrt{1+16}=\sqrt{17}

In the triangle QNP, the sides can be calculate as following:

  • Q(-4;4); N(-3;0)

             => QN = \sqrt{[-3-(-4)]^{2} + (0-4)^{2}  } = \sqrt{1^{2}+(-4)^{2}  } = \sqrt{1+16}=\sqrt{17}

  • Q (-4;4); P(-7;1)

   => QP = \sqrt{[-7-(-4)]^{2} + (1-4)^{2}  } = \sqrt{(-3)^{2}+(-3)^{2}  } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}

  • N(-3;0); P(-7;1)

             =>  NP = \sqrt{[-7-(-3)]^{2} + (1-0)^{2}  } = \sqrt{(-4)^{2}+1^{2}  } = \sqrt{16+1}=\sqrt{17}

It can be seen that QPN and JKL have: JK = QN; JL = QP; KL = NP

=> They are congruent triangles

7 0
3 years ago
Read 2 more answers
A square with a side length of 3 units is dilated with a scale factor of 2.
Anna [14]
<h3> - - - - - - - - - - - - - ~<u>Hello There</u>!~ - - - - - - - - - - - - - </h3>

➷Simply multiply by 2:

3 x 2 = 6

It would be 6 units

➶Hope This Helps You!

➶Good Luck :)

➶Have A Great Day ^-^

↬ Hannah ♡

3 0
4 years ago
What is the value of the expression 5x2 + 2x when x = 5?
masha68 [24]

Answer:

135

Step-by-step explanation:

Given:

x = 5

To determine a numerical value for the expression, simply substitute the value of "x" into the expression and simplify the expression, if necessary, to determine a specific number for the expression provided.

  • \implies 5x^{2}  + 2x
  • \implies 5(5)^{2}  + 2(5) \longrightarrow \longrightarrow \longrightarrow (x = 5)
  • \implies 5(5)(5)  + 2(5)
  • \implies 125  + 10
  • \implies 135

Therefore, the value of the expression 5x^{2}  + 2x when x = 5 is 135.

Learn more about this topic: brainly.com/question/27675691

7 0
2 years ago
What is - 4i ^ 19, simplify
german

Answer:

"i"

Step-by-step explanation:

i =\sqrt{-1} \\i^{2}= -1\\\\i^{3}= -i\\\\i^{4}= 1\\\\i^{5}= i\\

the cycle repeats every 4

19/4 = 4.75

16 is divisible by 4 plus three more

thus  i^{19} = -i  but you problem has a minus in front  so "i"

7 0
3 years ago
Need help plz help me pls
Orlov [11]
The answer u are looking for is 30
8 0
3 years ago
Read 2 more answers
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