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3 years ago

Find m A. 20 B. 40 C. 60 D.120

Mathematics

2 answers:

KonstantinChe [14]3 years ago

7 0

The answer is C.

I only know this because it is an acute angle so "D" is wrong. It is also too wide to be "A" or "B" so the only of that is left is "C". through process of elimination.

Hatshy [7]3 years ago

4 0

∠FEG is an exterior angle.
An exterior angle of a triangle is equal to the sum of the opposite interior angles, so

2x + x = x + 40
3x = x + 40
3x - x = 40
2x = 40
x = 20

m∠FEG = x+40 = 20+40 = 60°

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prisoha [69]

Answer:

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Crank

Given:

The graph of a line.

To find:

The equation of the line.

Solution:

From the given graph, it is clear that the line passes through the points (0,-2) and (-6,8). So, the equation of the line is:

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3 years ago

How do you solve this problem

Kryger [21]

Answer:

$sin(A) = \frac{21}{{29} }$

$cos(A)=\frac{20}{29 }$

$tan(A)=\frac{21}{20}$

$sin(C) = \frac{20}{{29} }$

$cos(C)=\frac{21}{29 }$

$tan(C)=\frac{20}{21}$

Step-by-step explanation:

So first we need to make sure we know the trig identities to solve this problem.

$sin(\alpha )=\frac{opposite}{hypotenuse}$
$cos(\alpha )=\frac{adjacent}{hypotenuse}$
$tan(\alpha )=\frac{opposite}{adjacent}$

Here we only have two legs of the triangle, so we will need to use the Pythagorean Theorem a² + b² = c² to solve for the missing leg, the hypotenuse in this case.

Solving for the hypotenuse, c, we get $c = \sqrt{a^{2} +b^{2} }$
Here a = 20 and b = 21, so plugging in these values to the equation we get: $c= \sqrt{(20)^{2}+(21)^{2} } =\sqrt{400+441} =\sqrt{841}=29$

Now we can use the trig identities to figure out the missing values for the problem

$sin(A) = \frac{21}{{29} }$
$cos(A)=\frac{20}{29 }$
$tan(A)=\frac{21}{20}$
$sin(C) = \frac{20}{{29} }$
$cos(C)=\frac{21}{29 }$
$tan(C)=\frac{20}{21}$

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