Perform the indicated operation. 6/11

In this problem, we explore the effect on the mean, median, and mode of multiplying each data value by the same number. Consider

andreev551 [17]

Answer:

a) Mean = 4.6, median = 3, mode =2

b) Mean = 13.8, median = 9, mode = 6

c) Option C) Multiplying each data value by the same constant c results in the mode, median, and mean increasing by a factor of c

Step-by-step explanation:

We are given the following data:

2, 2, 3, 6, 10

a) Mean, median and mode

Sorted data: 2, 2, 3, 6, 10

Mode is the most frequent observation in data.

Mode = 2

b) Multiplying data set by 3

6, 6, 9, 18, 30

Mode = 6

C) Comparison

The mean, median and mode of the new data increased by a factor of 3.

Option C) Multiplying each data value by the same constant c results in the mode, median, and mean increasing by a factor of c

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6 0

3 years ago

Which of the following would best be solved using factoring the difference of squares? 2² + 3x - 10 = 0 O 3r² + 12x = 8 2³ +52²

IgorC [24]

Given: Different equations

To Determine: Which would be best solved using difference of two squares

Solution

The factorization of a difference of two squares is given below

$a^2-b^2=(a-b)(a+b)$

Let us examine each of the given equation

$\begin{gathered} x^2+3x-10=0 \\ x^2-2x+5x-10=0 \\ x(x-2)+5(x-2)=0 \\ (x-2)(x+5)=0 \end{gathered}$ $\begin{gathered} 3x^2+12x=8 \\ 3x^2+12x-8=0 \end{gathered}$ $\begin{gathered} x^3+5x^2-9x-45=0 \\ x^2(x+5)-9(x+5)=0 \\ (x+5)(x^2-9)=0 \\ x^2-9=x^2-3^2=(x+3)(x-3) \\ Therefore \\ (x+5)(x+3)(x-3)=0 \end{gathered}$ $\begin{gathered} x^2-25=0 \\ x^2-5^2=0 \\ (x+5)(x-5)=0 \end{gathered}$

From the above,

$\begin{gathered} x^3+5x^2-9x-45=0 \\ AND \\ x^2-25=0 \end{gathered}$

The two equation above can be solved by difference of two square, but the equation below is the easiest solved using differnce of two square

x² - 25 = 0

3 0

1 year ago

The Wilson family had 5 children. Assuming that the probability of a child being a girl is 0.5, find the probability that the Wi

Dafna11 [192]

Answer:

0.813

0.500

Step-by-step explanation:

Use binomial probability.

P = nCr p^r q^(n−r)

where n is the number of trials,

r is the number of successes,

p is the probability of success,

and q is the probability of failure (1−p).

In this problem, n = 5, p = 0.5, and q = 0.5.

"At least 2 girls" means r = 2, 3, 4, or 5.

Or, we can use the complement.

P(at least 2 girls) = 1 − P(at most 1 girl)

P(at least 2 girls) = 1 − P(r=0 or r=1)

P(at least 2 girls) = 1 − ₅C₁ (0.5)¹ (0.5)⁵⁻¹ − ₅C₀ (0.5)⁰ (0.5)⁵⁻⁰

P(at least 2 girls) = 1 − 5 (0.5) (0.5)⁴ − 1 (1) (0.5)⁵

P(at least 2 girls) = 1 − 6 (0.5)⁵

P(at least 2 girls) ≈ 0.813

"At most 2 girls" means r = 0, 1, or 2.

P(at most 2 girls) = P(r=0, r=1, or r=2)

P(at most 2 girls) = ₅C₀ (0.5)⁰ (0.5)⁵⁻⁰ + ₅C₁ (0.5)¹ (0.5)⁵⁻¹ + ₅C₂ (0.5)² (0.5)⁵⁻²

P(at most 2 girls) = 1 (1) (0.5)⁵ + 5 (0.5) (0.5)⁴ + 10 (0.5)² (0.5)³

P(at most 2 girls) = 16 (0.5)⁵

P(at most 2 girls) = 0.500

4 0

3 years ago

The area of a floor is 48 ft2. If 20% of the floor is covered with an area rug, hue much floor is space remains uncovered

SCORPION-xisa [38]

The answer is 9.6 hope this helped you

7 0

3 years ago

Read 2 more answers

Consider the sequence 1, –3, 9, –27, 81, … Which statement describes the sequence?

ludmilkaskok [199]

Answer:

There is a similar problem with the same numbers except with no negatives so it goes 1 , 3 , 9 , 27, 81 for this question the answer is that it diverges.

Step-by-step explanation:

It was on the unit test review for edge and the answer was that it diverges.

8 0

3 years ago

Read 2 more answers

Perform the indicated operation. 6/11 - 4/11. 1/11 2/11 10/11