Slope Intercept: Y=mx + b
1. Y= -2/3x + -4
2. Y= 1/3x + 7
Answer:
See Below.
Step-by-step explanation:
We are given that ΔAPB and ΔAQC are equilateral triangles.
And we want to prove that PC = BQ.
Since ΔAPB and ΔAQC are equilateral triangles, this means that:
Likewise:
Since they all measure 60°.
Note that ∠PAC is the addition of the angles ∠PAB and ∠BAC. So:
Likewise:
Since ∠QAC ≅ ∠PAB:
And by substitution:
Thus:
Then by SAS Congruence:
And by CPCTC:
Answer: 23600000
Step-by-step explanation:
Answer:
The median is usually preferred in these situations because the value of the mean can be distorted by the outliers. However, it will depend on how influential the outliers are. If they do not significantly distort the mean, using the mean as the measure of central tendency will usually be preferred.
Answer:
The correct order is:
a
c
d
b
Step-by-step explanation:
First, let's write 1/x in a convenient way for us:
a) Substitute 1/x = p/q, to obtain x = 1/(1/x) = 1/(p/q) = q/p.
Now we assume that 1/x is rational (we want to prove that this implies that x will be also rational and because we know that x is irrational assuming that 1/x is rational will lead to an incongruence), then:
c. If 1/x is rational, then 1/x = p/q for some integers p and q with q ≠ 0. Observe that p is not 0 either, because 1/x is not 0.
Now we know that we can write x as a quotient of two integers, we need to imply that, then the next one is:
d) Observe that x is the quotient of two integers with the denominator nonzero.
And that is the definition of rational, then we end with:
b) Hence x is rational.
Which is what we wanted to get.
