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vesna_86 [32]
2 years ago
5

Solve the inequality 4(n-3)- 6 > 18

Mathematics
2 answers:
Sonbull [250]2 years ago
8 0

Answer:

n>9

Step-by-step explanation:

4(n-3)- 6 > 18

To solve this inequality we need to remove the parenthesis

distribute 4 inside the parenthesis

4n -12 - 6 > 18

Now combine like terms

4n - 18 > 18

We need to isolate 'n', so we add 18 on both sides

4n > 36

Now divide both sides by 4

n > 9

So the value of n is greater than 9


Sphinxa [80]2 years ago
4 0

Answer:

n >9

Step-by-step explanation:

4(n-3)- 6 > 18

Distribute the 4

4n-12 - 6 > 18

Combine like terms

4n -18 > 18

Add 18 to each side

4n-18+18 > 18+18

4n > 36

Divide by 4

4n/4 > 36/4

n >9

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Please calculate this limit <br>please help me​
Tasya [4]

Answer:

We want to find:

\lim_{n \to \infty} \frac{\sqrt[n]{n!} }{n}

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Because here we are taking the limit when n tends to infinity, we can use this approximation.

Then we get.

\lim_{n \to \infty} \frac{\sqrt[n]{n!} }{n} = \lim_{n \to \infty} \frac{\sqrt[n]{\sqrt{2*\pi*n} *(\frac{n}{e} )^n} }{n} =  \lim_{n \to \infty} \frac{n}{e*n} *\sqrt[2*n]{2*\pi*n}

Now we can just simplify this, so we get:

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And we can rewrite it as:

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The important part here is the exponent, as n tends to infinite, the exponent tends to zero.

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2 years ago
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Whole= X
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