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3 years ago

Solve the inequality 4(n-3)- 6 > 18

Mathematics

2 answers:

Sonbull [250]3 years ago

8 0

Answer:

n>9

Step-by-step explanation:

4(n-3)- 6 > 18

To solve this inequality we need to remove the parenthesis

distribute 4 inside the parenthesis

4n -12 - 6 > 18

Now combine like terms

4n - 18 > 18

We need to isolate 'n', so we add 18 on both sides

4n > 36

Now divide both sides by 4

n > 9

So the value of n is greater than 9

Sphinxa [80]3 years ago

4 0

Answer:

n >9

Step-by-step explanation:

4(n-3)- 6 > 18

Distribute the 4

4n-12 - 6 > 18

Combine like terms

4n -18 > 18

Add 18 to each side

4n-18+18 > 18+18

4n > 36

Divide by 4

4n/4 > 36/4

n >9

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Solve x^2-6x+25 = 0 by completing the square.

Oksana_A [137]

First, subtract both sides by 25:

x^2 - 6x = -25

Because we're completing the square, we subtract both sides by 9:

x^2 - 6x - 9 = -34

(x - 3) = 5.831 (about)

x = 8.831

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3 years ago

What divided by 40.01 is close to 1

Dimas [21]

Answer:

40.01

Step-by-step explanation:

40.01÷40.01= 1

So the answer is 1 bcs if u have 3 glasses of water and divide them by 3 each will have one and this is the same with another number

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3 years ago

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A random sample of 121 automobiles traveling on an interstate showed an average speed of 65 mph. From past information, it is kn

loris [4]

Answer:

95 percent confidence interval for μ is determined by

(60.688 , 69.312)

a) be the same

Step-by-step explanation:

Step (i):-

Given data a random sample of 121 automobiles traveling on an interstate showed an average speed of 65 mph.

The sample size is n= 121

The mean of the sample x⁻ = 65mph.

The standard deviation of the population is 22 mph

σ = 22mph

Step (ii) :-

Given The 95 percent confidence interval for μ is determined as

(61.08, 68.92)

we are to reduce the sample size to 100 (other factors remain unchanged) so

given The sample size is n= 100

The mean of the sample x⁻ = 65mph.

The standard deviation of the population is 22 mph

σ = 22mph

Step (iii):-

95 percent confidence interval for μ is determined by

$(x^{-} - 1.96\frac{S.D}{\sqrt{n} } , x^{-} + 1.96 \frac{S.D}{\sqrt{n} } )$

$(65 - 1.96\frac{22}{\sqrt{100} } , 65 + 1.96 \frac{22}{\sqrt{100} } )$

(65 - 4.312 ,65 +4.312)

(60.688 , 69.312) ≅(61 ,69)

This is similar to (61.08, 68.92) ≅(61 ,69)

Conclusion:-

it become same as (61.08, 68.92)

4 0

3 years ago

Twice the sum of a number and 3 is equal to three times the difference of the number and 3

lana66690 [7]

Twice the sum of a number and 3 = 2(n + 3)
three times the difference of the number and 3 = 3(n - 3)
so
Twice the sum of a number and 3 is equal to three times the difference of the number and 3:
2(n + 3) = 3(n - 3)
2n + 6 = 3n - 9
n = 15

answer
2(n + 3) = 3(n - 3)
n = 15

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3 years ago

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What is the area of this figure?

Hunter-Best [27]

Answer:

just a guess I would say 70cm squared.

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2 years ago