Answer:
i'm just a kid ku ku ku ku ku ku ku ku ku ku ku ku
Answer:
def analyze_text(sentence):
count = 0
e_count = 0
for s in sentence:
s = s.lower()
if s.isalpha():
count += 1
if s == "e":
e_count += 1
return "The text contains " + str(count) + " alphabetic characters, of which " + str(e_count) + " (" + str(e_count*100/count) + "%) are ‘e’."
Explanation:
Create a function called analyze_text takes a string, sentence
Initialize the count and e_count variables as 0
Create a for loop that iterates through the sentence
Inside the loop, convert all letters to lowercase using lower() function. Check each character. If a character is a letter, increment the count by 1. If a character is "e", increment the e_count by 1.
Return the count and e_count in required format
Answer: .com — Commercial businesses.
.org — Organizations (generally charitable).
.net — Network organizations.
.gov — U.S. government agencies.
.mil — Military.
.edu — Educational facilities, like universities.
Explanation:
Answer:
if (x > 7 && Math.sqrt(x) < 3)
Explanation:
The previous condition checks if the square root of x is less than 3, but this would raise an error if x is a value equal to or less than 0.
So, the condition checks for the value of x before evaluating the square root after the AND operation to prevent an arithmetic exception.
