Answer:
Hi!
The correct answer is E.
Explanation:
void change(int ar[], int low, inthigh) {
int temp;
if(low< high) { <em>// here ask if the positions low and high of the array are the same.</em>
temp= ar[low]; <em>// first, saves the element on ar[low] in temp.</em>
ar[low]= ar[high]; <em>// second, the element on ar[high] in ar[low]. First switch.</em>
ar[high]= temp; <em>// third, saves the element on temp in ar[high]. Complete switch.</em>
change(ar,low + 1, high - 1); <em>// Recursive call, adding one position to low, and subtracting one position to high. </em><em>Important: </em><em>When low and high have the same value, the recursive call will finish.</em>
}
}
Result: Switch the lower half of elements in the array with the upper half.
<span>Consider
the cement used for the foundation; the bricks and timber used for the
walls; and the shingles used for the roof. All of these are __________
in making the house.
A. Elements</span>
Answer: a replay attack, a replay attack is used so that the attacker can go sniff out the hash, and get whatever they are trying to get, then once it goes to the attacker it will go back to the original connection after replaying the hash
Answer:
Information and communications technology is an extensional term for information technology that stresses the role of unified communications and the integration of telecommunications and computers, as Technology Trends 2016
#1: Spreading intelligence throughout the cloud. ...
#2: Self-managing devices. ...
#3: Communication beyond sight and sound. ...
#4: Fundamental technologies reshaping what networks can do. ...
#5: Weaving security and privacy into the IoT fabric.
Explanation:
look for a question that i have answered answer it and also plz give me brainliest on this one plz
Answer:
// This program is written in C++
// Comments are used for explanatory purpose
// Program starts here
#include<iostream.h>
#include<stdlib.h>
int main()
{
// Declare variables
int num, selectno;
string status;
randomize();
//Generate random number;
num=rand()%10000;
// Prompt to guess a number
cout<<"You have only 10 tries\nTake a guess: ";
int tries = 0;
while (tries != 10)
{
cin>>selectno;
if(selectno == num){
cout<<"You passed at the "<<count+1<<" attempt";
tries = 10;
}
else
{
cout<<"You failed. Take another guess\n You have "<<10 - count + 1 <<" attempts";
}
tries++;
if(tries >= 10)
{
break;
}
}
return 0;
}
