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ELEN [110]
3 years ago
7

Which polynomial is factored completely? A.(4x+4) (x+1) B. 3n4 - 15n3 + 12n2 C. 121x2 + 36y D. 2x (x2-4)

Mathematics
1 answer:
morpeh [17]3 years ago
3 0
B. 3n^4 - 15n^3 + 12n^2
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Percentages What percentage is R10 of R200? R10 100 X R200 <br>​
Andrej [43]

R10 is 5% of R200

<h3>What percentage is R10 of R200?</h3>

The given parameters are:

R10 of R200

The percentage is calculated as

Percentage = R10/R200 * 100%

Evaluate the product

Percentage = 5%

Hence, R10 is 5% of R200

Read more about percentage at:

brainly.com/question/843074

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8 0
2 years ago
Consider the probability that greater than 96 out of 153 DVDs will work correctly. Assume the probability that a given DVD will
ICE Princess25 [194]

Answer:

0.3594 = 35.94% probability that greater than 96 out of 153 DVDs will work correctly.

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 153, p = 0.62

So

\mu = E(X) = np = 153*0.62 = 94.86

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{153*0.62*0.38} = 6

Probability that greater than 96 out of 153 DVDs will work correctly.

97 or more DVDs, which is 1 subtracted by the pvalue of Z when X = 97. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{97 - 94.86}{6}

Z = 0.36

Z = 0.36 has a pvalue of 0.6406

1 - 0.6406 = 0.3594

0.3594 = 35.94% probability that greater than 96 out of 153 DVDs will work correctly.

3 0
3 years ago
X+3y=5
DerKrebs [107]

Answer:

That all the answer  hope i helped


8 0
3 years ago
Read 2 more answers
( wil give branliest) I need help. thank you
Lisa [10]
Tbh 8778188778654789644477 I’m am a 90 old man
7 0
3 years ago
What is the eighth term of the sequence that begins with 1, 3, 7, 13, 21, ... ?
otez555 [7]

31 because it is adding 2 to each number

7 0
2 years ago
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