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3 years ago

Graph the following y = 4/3 x + 8

Mathematics

2 answers:

Trava [24]3 years ago

7 0

Answer:

Step-by-step explanation:

Phantasy [73]3 years ago

5 0

Answer :)

Used an Algebra Problem Solver

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Christian gave keven 6 blueberries. Keven gave San 6 blueberries how much dose Keven have left

il63 [147K]

Answer:

So if Keven started with 0 he then got 6 then gave it away, that means he simply had none to himself.

4 0

3 years ago

Simplify the expression: z8 * z-3

MissTica

Answer:

z^5

Step-by-step explanation:

z^8 * z^-3

Since we are multiplying exponents and the bases are the same, we can add the exponents

z^(8-3)

z^5

3 0

3 years ago

Quadrilateral OPQR is inscribed inside a circle as shown below. What is the measure of angle O? You must show all your work.

likoan [24]

Answer:

88 deg

Step-by-step explanation:

Opposite angles of an inscribed quadrilateral are supplementary. That means that the sum of the measures of angles O and Q is 180 deg.

2x + 2x + 4 = 180

4x + 4 = 180

4x = 176

x = 44

m<O = 2x = 2(44) = 88

Answer: 88 deg

4 0

3 years ago

There are 12 inches in 1 foot. Write 75 inches in feet and inches

mixas84 [53]

84/12 is 7 so it’s 7 feet and to find out how many inches, you have to subtract 84-75 which is 9 that that’s 9 inches

7 feet and 9 inches

6 0

3 years ago

Read 2 more answers

Two vertical poles of lengths 11 ft and 14 ft stand 16 ft apart. A cable reaches from the top of one pole to some point on the g

Alex17521 [72]

We are given

total length of cable is 30 feet

and this cable is on hypotenuse sides of the triangles

so, we can draw triangle as

Let's assume those hypotenuse as 'a' and 'b'

so, we will have

$a+b=30$

now, we can find 'a' and 'b' from triangle

Smaller triangle:

$a=\sqrt{x^2+11^2}$

Larger triangle:

$b=\sqrt{(16-x)^2+14^2}$

we know that

$a+b=30$

so, we can plug this value

and we get

$\sqrt{x^2+11^2}+\sqrt{(16-x)^2+14^2} =30$

now, we can solve for x

$\left(\sqrt{x^2+11^2}\right)^2=\left(30-\sqrt{\left(16-x\right)^2+14^2}\right)^2$

$32x-1231=-60\sqrt{x^2-32x+452}$

$1024x^2-78784x+1515361=3600x^2-115200x+1627200$

now, we can use quadratic formula

we get

$x=\frac{-\sqrt{36416^2-1152389056}+36416}{5152},\:x=\frac{\sqrt{36416^2-1152389056}+36416}{5152}$

$x=4.510,x=9.627$

so,

The point should be located 4.510 feet , 9.627 feet from the smaller pole to use 30 feet cable............Answer

6 0

3 years ago