For m = 0.6213,
For m = -3.6213,
Therefore, the equation has no extraneous solution.
in this problem what you are really looking for is which of these sets is a pathagorean triple. That means it will solve the pathagorean theorem. (a sqaured + b squared = c squared) c is always going to be the largest number or the hypotenuse. if you plug all the number sets into the theorem, only one works and that is 7, 24, 25 which is your answer.
Answer:
Graph will open same way and is narrower.
Step-by-step explanation
If: f(x)= x^4
f(-2x)= (-2x)^4
Negative sign usually flips the graph and make it open to the opposite direction. In this case since the function is to the 4th degree and the negative sign is included. The negative is basically ignored.
The term in front of x (a) determines how wide the graph opens. The bigger the a value the faster the slope increases so the narrower the graph opens.
Think if the slope is 4 vs 1/4.
Hope this helps
Answer:
x = -2
Step-by-step explanation:
![f(x) =x^2 -2x\:\: and \:\: g(x) = 6x + 4\\(f+g)(x) = f(x) + g(x) \\(f+g)(x) = x^2 -2x+ 6x + 4\\(f+g)(x) = x^2+4x + 4\\(f+g)(x) = (x+2)^2\\ 0 = (x+2)^2...[\because (f+g)(x) =0]\\0 = x+2\\\therefore x = -2](https://tex.z-dn.net/?f=f%28x%29%20%3Dx%5E2%20-2x%5C%3A%5C%3A%20and%20%5C%3A%5C%3A%20g%28x%29%20%3D%206x%20%2B%204%5C%5C%28f%2Bg%29%28x%29%20%3D%20f%28x%29%20%2B%20g%28x%29%20%5C%5C%28f%2Bg%29%28x%29%20%3D%20x%5E2%20-2x%2B%206x%20%2B%204%5C%5C%28f%2Bg%29%28x%29%20%3D%20x%5E2%2B4x%20%2B%204%5C%5C%28f%2Bg%29%28x%29%20%3D%20%28x%2B2%29%5E2%5C%5C%200%20%3D%20%28x%2B2%29%5E2...%5B%5Cbecause%20%28f%2Bg%29%28x%29%20%3D0%5D%5C%5C0%20%3D%20x%2B2%5C%5C%5Ctherefore%20x%20%3D%20-2)
