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3 years ago

Ignore them workings out. Can someone show me how to work this out

Mathematics

1 answer:

Readme [11.4K]3 years ago

7 0

So, i did this,
7.8*10=70
and then add 12
i got 82
did this help??

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Find the volume of a cylinder below . The formula for the volume of a cylinder is . The radius of the circle is represented by r

lapo4ka [179]

Answer:

The volume of the cylinder V = 942 cm³

Step-by-step explanation:

Step(i):-

Given that the graph

The height of the cylinder (h) = 12cm

The diameter of the cylinder d = 10cm

The radius of the cylinder

d = 2r

r = $\frac{10}{2}$

r = 5 cm

Step(ii):-

The Volume of the cylinder

V = π r² h

V = π (5)²(12)

V = 300π cubic centimeter

V = 300 × 3.14

V = 942 cm³

Final answer:-

Volume of the cylinder V = 942 cm³

3 0

2 years ago

Problem 2 Find the mBC.

MatroZZZ [7]

Answer:

38º

Step-by-step explanation:

<BAC is a central angle. The corresponding arc, BC will be equal to the measure of the central angle.

So mBC = 38º

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3 years ago

If angle P is a right angle and angle P and Q from a linear pair, then angle Q is

anygoal [31]

< P is a right angle.....a right angle is 90 degrees.
< P and < Q form a linear pair....a linear pair, when added, = 180 degrees

so if < P is 90.....and when added to < Q = 180...
90 + Q = 180
Q = 180 - 90
Q = 90 <== so < Q is also a right angle...measures 90 degrees

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3 years ago

What is Pythagorean’s theorem??

Alchen [17]

Answer:

HOPE it's helpful

......

5 0

3 years ago

Read 2 more answers

lim x rightarrow 0 1 - cos ( x2 ) / 1 - cosx The limit has to be evaluated without using l'Hospital'sRule.

zaharov [31]

Answer with Step-by-step explanation:

Given

$f(x)=\frac{1-cos(2x)}{1-cos(x)}\\\\\lim_{x \rightarrow 0}f(x)=\lim_{x\rightarrow 0}(\frac{1-(cos^2{x}-sin^2{x})}{1-cos(x)})\\\\(\because cos(2x)=cos^2x-sin^2x)\\\\\lim_{x \rightarrow 0}f(x)=\lim_{x\rightarrow 0}(\frac{1-cos^2x}{1-cos(x)}+\frac{sin^2x}{1-cosx})\\\\=\lim_{x\rightarrow 0}(\frac{(1-cosx)(1+cosx)}{1-cosx}+\frac{sin^2x}{1-cosx})\\\\=\lim_{x\rightarrow 0}((1+cosx)+\frac{sin^2x}{1-cosx})\\\\\therefore \lim_{x \rightarrow 0}f(x)=1$

6 0

2 years ago