The length of a rectangle is two feet greater than twice its width. If the perimeter is 25 feet, find the width

Mathematics

1 answer:

Blababa [14]4 years ago

6 0

The width would be 3.5 feet

hope this helps

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Convert: 6y + y² = x² from rectangular to polar form.

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$\bf \textit{Double Angle Identities}
\\ \quad \\
sin(2\theta)=2sin(\theta)cos(\theta)
\\ \quad \\\\
cos(2\theta)=
\begin{cases}
\boxed{cos^2(\theta)-sin^2(\theta)}\\
1-2sin^2(\theta)\\
2cos^2(\theta)-1
\end{cases}\\\\\\
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-------------------------------\\\\$

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\cfrac{6rsin(\theta )}{r^2cos^2(\theta )}+\cfrac{r^2sin^2(\theta )}{r^2cos^2(\theta )}=1\implies 
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$\bf \cfrac{6sin(\theta )}{rcos^2(\theta )}=1-\cfrac{sin^2(\theta )}{cos^2(\theta )}\implies \cfrac{6sin(\theta )}{1-\frac{sin^2(\theta )}{cos^2(\theta )}}=rcos^2(\theta )
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\cfrac{6sin(\theta )}{cos^2(\theta )\left[ 1-\frac{sin^2(\theta )}{cos^2(\theta )} \right]}=r\implies \cfrac{6sin(\theta )}{cos^2(\theta )-sin^2(\theta )}=r
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\cfrac{6sin(\theta )}{cos(2\theta )}=r$

5 0

3 years ago

If anyone can help that will be great!

dybincka [34]

Answer:

Step-by-step explanation:

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3 years ago

Read 2 more answers

The two triangles are similar what is the value of x? <br> x=___

Dennis_Churaev [7]

Answer:

Step-by-step explanation:

What we have to know is that when two triangles are similar their sides will always be proportional. So we will create a proportion that goes like this... $\frac{\Delta1side}{\Delta1base} =\frac{\Delta2side}{\Delta2base}$ but since it doesn't tell us the exact value of triangle 1. We will have to add 3 and 12 to get 15 which is the base of the first triangle. Now we're ready to write the proportion.