The length of a rectangle is two feet greater than twice its width. If the perimeter is 25 feet, find the width

Solve the triangle. a = 10, b = 23, C = 95°

gayaneshka [121]

C² = a² + b² - (2ab * cosC)
c² = 10² + 23² - (2 * 10 * 23 * cos95) 
c² = 100 + 529 - (460 * -.08715) 
c² = 629 - (-40.1) 
c² = 669.1 
c = 25.87 

(Sin C) / C = (Sin A) / A 
(Sin 95) / 25.87 = SinA / 10, Remember 0 < A < 85 
(10 * Sin95) / 25.87 = Sin A 
A = arcsin ((10 * sin95) / 25.87) 
A = 22.65º 

B = 180 - A - C 
B = 180 - 95 - 22.65 
B = 62.35º 

I hope this helps. Have a good day.

3 0

4 years ago

The graph shows the function g. Which of the following statements is NOT true? *

USPshnik [31]

Answer:

The figure above shows the graph of a function f with domain 0 ≤ x ≤ 4. Which of the following statements are true? Show Video ... If there is no c, where -2 < c < 2, for which f'(c) = 0, which of the following statements must be true? Show Video ...

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Runner A is initially 6.0 km west of a flagpole and is running with a constant velocity of 3.0 km/h due east. Runner B is initia

ArbitrLikvidat [17]

Answer:

The distance of the two runners from the flagpole is 0.0882 km

Step-by-step explanation:

We are going to use the minus sign when the runner is on the west and the plus sign when the runner is on the east.

Then, Taking into account the runner A is 6 km west and is running with a constant velocity of 3 Km/h east, the distance of the runner A from the flagpole is given by the following equation:

Xa = -6 Km + (3 Km/h)* t

Where Xa is the position of the runner A from the flagpole and t is the time in hours.

At the same way the distance of the runner B, Xb, from the flagpole is given by the following equation:

Xb = 7.4 Km - (3.8 Km/h)*t

Then, the two runners cross their path when Xa is equal to Xb, so if we solve this equation for t, we get:

Xa = Xb

-6 + (3*t) = 7.4 - (3.8*t)

(3.8*t) + (3*t) = 7.4 + 6

(6.8*t) = 13.4

t = 13.4/6.8

t = 1.9706

Therefore, at time t equal to 1.9706 hours, both runners cross their path. The distance of the two runners from the flagpole can be calculated replacing the value of t in equation for Xa or in equation for Xb as:

Xa = -6 Km + (3 Km/h)* t

Xa = -6 Km + (3 Km/h)*(1.9706 h)

Xa = -0.0882 Km

That means that both runners are 0.0882 Km west of a flagpole.

4 0

3 years ago

Please help I dont understand

Anastasy [175]

Answer:

Angle 2=160

Angle 3=10

Step-by-step explanation: