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DiKsa [7]
4 years ago
14

Given the quantities a= 9.7 m, b= 4.2 s, c= 69 m/s, what is the value of the quantity d = a^3/(cb^2)?

Physics
2 answers:
nexus9112 [7]4 years ago
7 0
D= 9.7^3/(69)(4.2)^2
d=912.673/289.8^2
d=912.673/83984.04
d=0.01086721953362...
I hope this helped!
juin [17]4 years ago
3 0
Answer = a^3 / c.b^2

A = (9,7m)^(3) / 69m/s×(4,2s)^(2)

A = 912,673m^(3)/ 69m/s ×17,64s^2

A = 912,673m^(3) / 1.217,16m.s

A = 0,749838147 m^(2)/s

Or

A = 7,5 × 10^(-1) m^(2)/s
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