Answer:
The work done on the athlete is approximately 2.09 J
Explanation:
From the definition of the work done by a variable force:
![\displaystyle{\int_{x_i}^{x_j}F(x)dx}](https://tex.z-dn.net/?f=%5Cdisplaystyle%7B%5Cint_%7Bx_i%7D%5E%7Bx_j%7DF%28x%29dx%7D)
and substituting with the function of our problem:
![\displaystyle{\int_{0}^{0.19}(140x-190x^2)dx\approx2.09\mathrm{J}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%7B%5Cint_%7B0%7D%5E%7B0.19%7D%28140x-190x%5E2%29dx%5Capprox2.09%5Cmathrm%7BJ%7D%7D)
Data:
mass, m = 30.94 g
density, d = 19.32 g/cm^3
Formula: d = m / v => v = m / d = 30.94 g / 19.32 g/cm^3 = 1.60 cm^3
Then, the answer is the option C.
![\huge\mathfrak\red {Answer:}](https://tex.z-dn.net/?f=%5Chuge%5Cmathfrak%5Cred%20%7BAnswer%3A%7D)
<h2>Speed = Distance/Time</h2>
If a train travelled 500 meters in 25 seconds then,
Speed = 500m/25sec
<h2>
→ 20 m/sec</h2>
![\mathfrak\purple {Hope\: this\: helps\: you...}](https://tex.z-dn.net/?f=%5Cmathfrak%5Cpurple%20%7BHope%5C%3A%20this%5C%3A%20helps%5C%3A%20you...%7D)