To develop this problem it is necessary to apply the concepts of sum of capacitors in a circuit, either in parallel or in series.
When capacitors are connected in series, they consecutively add their capacitance.
However, when they are connected in parallel, the sum that is made is that of the inverse of the capacitance, that is where, C is the capacitance.
For the given case, it is best to connect two of these capacitors in series and one in parallel, so
We have three 100 pF capacitors, then
Here we can see how two capacitors 1 and 2 are in series and the third in parallel.
Investing equality
Adding it in parallel, then
Answer:
option B...
they represent different concept...
i hope this will answer your question
Answer:
z = 0.8 (approx)
Explanation:
given,
Amplitude of 1 GHz incident wave in air = 20 V/m
Water has,
μr = 1
at 1 GHz, r = 80 and σ = 1 S/m.
depth of water when amplitude is down to 1 μV/m
Intrinsic impedance of air = 120 π Ω
Intrinsic impedance of water =
Using equation to solve the problem
E(z) is the amplitude under water at z depth
E_o is the amplitude of wave on the surface of water
z is the depth under water
now ,
taking ln both side
21.07 x z = 16.81
z = 0.797
z = 0.8 (approx)
Answer:
Explanation:
When we are dealing with Hall voltage, it is necessary to have the values of the current, the magnetic field, the length, the area and the number of carriers at hand. The Hall voltage equation is given by,
Where,
i= current
B= Magnetic field
L = Length
n = number of charge carriers
e= charge of a electron
We need replace and solve for n,
Therefore the density of charge carrier is
Work done by each is the same for they reach the same height. The one who climbs in 30s uses more power because work is done in a shorter time.