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Colt1911 [192]
3 years ago
12

Determine if the two figures are congruent and explain your answer.

Mathematics
2 answers:
spayn [35]3 years ago
8 0
They are not because congruent are <span>something that are the same but not in the same way.</span>
forsale [732]3 years ago
3 0
The two figures are congruent because the side lengths are the same, therefore making the angle measures the same.
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Slove for all the possible values of x. √21-4x=x-6
Alona [7]

Answer:

x=2.116

Step-by-step explanation:

\sqrt{21} -4x=x-6

4.58-4x-x=-6

-5x=-6-4.58

-5x=-10.58

x=2.116

4 0
3 years ago
What is the slope of the line that passes through the following points (7,10) and (10,9)
Svet_ta [14]

Answer:

-1/3

Step-by-step explanation:

To find the slope, we can use the slope formula

m = ( y2-y1)/(x2-x1)

    = ( 9-10)/(10-7)

    = -1/3

8 0
3 years ago
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100 points for correct answer
Tems11 [23]

Answer:

\dfrac{x}{3}+\dfrac{3}{y}

Step-by-step explanation:

<u>Given fraction</u>:

\dfrac{xy+9}{3y}

\textsf{Apply the fraction rule} \quad \dfrac{a+b}{c}=\dfrac{a}{c}+\dfrac{b}{c}:

\implies \dfrac{xy}{3y}+\dfrac{9}{3y}

Rewrite 9 as 3 · 3:

\implies \dfrac{xy}{3y}+\dfrac{3 \cdot 3}{3y}

Cancel the common factor y in the first fraction and the common factor 3 in the second fraction:

\implies \dfrac{x\diagup\!\!\!\!y}{3\diagup\!\!\!\!y}+\dfrac{\diagup\!\!\!\!3 \cdot 3}{\diagup\!\!\!\!3y}

\implies \dfrac{x}{3}+\dfrac{3}{y}

7 0
1 year ago
What are examples of ratio numbers please answer HELPPPPP
harina [27]
1 and 2, 3 und 5, etc

5 0
3 years ago
Find all real zeros of 4x^3-20x+16
Pani-rosa [81]

Answer:

  {1, (-1±√17)/2}

Step-by-step explanation:

There are formulas for the real and/or complex roots of a cubic, but they are so complicated that they are rarely used. Instead, various other strategies are employed. My favorite is the simplest--let a graphing calculator show you the zeros.

___

Descartes observed that the sign changes in the coefficients can tell you the number of real roots. This expression has two sign changes (+-+), so has 0 or 2 positive real roots. If the odd-degree terms have their signs changed, there is only one sign change (-++), so one negative real root.

It can also be informative to add the coefficients in both cases--as is, and with the odd-degree term signs changed. Here, the sum is zero in the first case, so we know immediately that x=1 is a zero of the expression. That is sufficient to help us reduce the problem to finding the zeros of the remaining quadratic factor.

__

Using synthetic division (or polynomial long division) to factor out x-1 (after removing the common factor of 4), we find the remaining quadratic factor to be x²+x-4.

The zeros of this quadratic factor can be found using the quadratic formula:

  a=1, b=1, c=-4

  x = (-b±√(b²-4ac))/(2a) = (-1±√1+16)/2

  x = (-1 ±√17)2

The zeros are 1 and (-1±√17)/2.

_____

The graph shows the zeros of the expression. It also shows the quadratic after dividing out the factor (x-1). The vertex of that quadratic can be used to find the remaining solutions exactly: -0.5 ± √4.25.

__

The given expression factors as ...

  4(x -1)(x² +x -4)

5 0
3 years ago
Read 2 more answers
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