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Rina8888 [55]
3 years ago
9

Work out the size of angle X.​

Mathematics
1 answer:
larisa [96]3 years ago
5 0

Answer:

x = 70°

Step-by-step explanation:

The external angle of a triangle is equal to the sum of the 2 opposite interior angles.

120° is an external angle of the triangle, thus

x + 50 = 120 ( subtract 50 from both sides )

x = 70

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Ques no 1 b) help me!!!!! <br> I will give you brainliest plzzz
saul85 [17]

Answer:

-4/5

Step-by-step explanation:

r=x/2

a=2x

ar²=-1/16

x^3=-1/8

x=-1/2

sn=a/1-r

=-4/5

6 0
3 years ago
Can you please help me?
Ivanshal [37]

5 x 5 = 25 numerator

6 x 8 = 48 denominator

Answer:

25/48

3 0
3 years ago
Use the table to work out the values of a, b,
Dvinal [7]
So to find the value of -3 do the following process:

Insert the -3 in the x’s in the equation on the top of the table

y= 5x -3x to the second power + 3

y= 5 (-3) -3(-3) to the second power + 3

Then continue to simplify the equation

y= -15 + 9 to the second power + 3

y= -15 + 84

y = 69

Y= 69 for the chart for -3

For b, c, and d insert the number in the x values and simplify like the previous equation.

If you are confused, feel free to ask questions. I hope this is effective and helps you in your studies.
4 0
2 years ago
I WILL GIVE BRAINLIEST PLEASE HELP ASAP!!!
Jlenok [28]

Answer:

Plzzz

Step-by-step explanation:

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4 0
3 years ago
If integer k is equal to the sum of all even multiples of 15 between 295 and 615, what is the greatest prime factor of k?
ohaa [14]

Answer:

The greatest prime factor of k is 11.

Step-by-step explanation:

∵  LCM( 2, 15) = 30,

Thus, the even multiple of 15 must be multiple of 30,

That is, the even multiple of 15 between 295 and 615 are

300, 330, 360,..........600

Which is an AP,

Having first term, a = 300,

Common difference, d = 30,

If n be the number terms,

Last term = a+(n-1)d

=300+(n-1)30

=270 + 30n

\implies 270+30n = 600\implies 30n = 330\implies n = 11

Hence, the sum of the all even multiple of 15 from 295 to 615,

S_{11}=\frac{11}{2}(2(300)+(11-1)30)=\frac{11}{2}(600+300)=\frac{11}{2}(900)=11\times 450

According to the question,

S_{11}=k

⇒ k = 11 × 450 = 11 × 5 × 5 × 3 × 3 × 2

Hence, the greatest prime factor of k is 11.

3 0
3 years ago
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