3m-9=9+3m
add 9 to both sides
3m=18+3m
minus 3m both sides
0=18
false
no solution
the best discription would be an empty solution set
Answer:
Construct MN.
Since M is the midpoint of OA, OM = MA
Similarly, N is the midpoint of OB.
Thus, ON = NB.
Now, in Δs OMN and OAB,
∠MON = ∠AOB (common angle)
(sides are in proportional ratio; OA = 2OM and OB = 2ON)
∴ Δs OMN and OAB are similar (2 sides are in proportion, with the included angle)
Since they are similar, then ∠OMN = ∠OAB (corresponding angles of similar triangles are equal)
But since ∠OMN = ∠OAB, then that means MN || AB (corresponding angles of two lines must be equal since they also sit relative to the transverse line, OA)
Thus, AB || MN (QED)
Answer:
For only the rectangle (that I've coloured in with red) I assume it would be 9 inches squared. However, when adding on the triangles on the side, it would be 9+3+3 = 15
Step-by-step explanation:
Answer:
2826 inches^2
Step-by-step explanation:
The general formula for the total surface area of a regular pyramid is
T.S.A.=12pl+B
Where p represents the perimeter of the base, l the slant height and B the area of the base.
The perimeter of the base is.
p=2L+2W
P=2*10+2*9
P=20+18
P= 38 inches
The area of the base is.
B=10*9
B=90in^2
T.S.A.=12(38)(6)+90
T.S.A=2736+90
T.S.A=2826 inches^2
Hence the paper needed is 2826 inches^2
