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kiruha [24]
3 years ago
11

What is 13 time 6 plus 3

Mathematics
1 answer:
inessss [21]3 years ago
3 0

Answer:

81

Step-by-step explanation:

13 * 6 is 78

78 + 3 is 81

~hope this helps~

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2. A parking lot holds 40 cars. There are 20 cars in the lot already. Which inequality can be solved to show all the
Pie
C I need to put 20 letters so yea the answer is C
7 0
3 years ago
I'm having trouble
Liono4ka [1.6K]
It would be B because you would take amelias age and take two away since todd is five years younger to get the a-5.
hope this helps :)
8 0
3 years ago
From class we learned that in 2010 the federal debt (in millions) was $13,561,623 and the population of the U.S. was 309 million
NemiM [27]
Question A: The per capita debt would be $43,888.75. 

Per capita means the amount per person. To find this amount, we need to take the total debt and divide it by the number of people.

13,561,623 divided by 309 = 43,888.75

For Question B, you will need to have the other CPI value from the table.
7 0
3 years ago
the sum of the ages of a man and his wife is at least 104 years if the man is x years old and the wife is x - 4 years old find t
larisa [96]

Answer:

x ≥ 54

Step-by-step explanation:

x+x-4 ≥ 104

2x ≥ 104 + 4

2x ≥ 108

x ≥ 54

6 0
3 years ago
1. Writing an equation for an exponential function by
Naya [18.7K]

Answer: 1) t(n)=0.6(2)^n

2) f(x)=10(5)^x

Step-by-step explanation:

1) Let the function that shows the thickness of the paper after n folds,

t(n) = ab^n         ---------(1)

Since, According to the question,

Initially the thickness of the paper = 0.6

That is, at n = 0, t(0) = 0.6

By equation (1),

0.6 = a(b)^0\implies 0.6 = a

Hence the function that shows the given situation,

t(n) = 0.6 b^n       -----------(2)

Again when we fold the paper the thickness of the paper will be doubled.

Thus, at n = 1, t(1) = 1.2

By equation (2),

1.2 = 0.6 b^1\implies 2 = b

Thus, the complete function is,

t(n) = 0.6 (2)^n    

2) Let the function that is passing through the points (-2, 2/5) and (-1,2),

f(x) = ab^x         ---------(1)

For f(x) = 2, x = -1

By equation (1),

2= ab^{-1}       ---------(2)

Also, For f(x) = 2/5, x = -2

Again, By equation (1),

\frac{2}{5}= a(b)^{-2}

\implies \frac{2}{5}=ab^{-1}b^{-1}=2b^{-1}

\implies \frac{2}{5}=\frac{2}{b}

\implies 2b=10

\implies b = 5

By substituting this value in equation (2),

We get, a = 10

Hence, from equation (1), the function that is passing through the points (-2, 2/5) and (-1,2),

f(x) = 10(5)^x

5 0
3 years ago
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