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NNADVOKAT [17]
3 years ago
6

0.0072 in expanded form

Mathematics
1 answer:
Ratling [72]3 years ago
5 0
Seventy-two ten-thousandths. Try and see if this correct
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Solve the inequality <br> 3(x-2)&gt;-3
wolverine [178]

Answer:

x>1

Step-by-step explanation:

m at h w ay

6 0
2 years ago
Cards with the numbers 1 through 40 are placed in a box and thoroughly shuffled.
MrRa [10]

9/40 + 2/40 = 11/40

hope this helps

7 0
3 years ago
Explain how to find the estimated sum of 5/8+2/9 . Make sure to include at least one type of model.
OverLord2011 [107]
In this expression you would have to use the PEMDAS method. First divide, so (5 divided by 8) + (2 divided by 9). 
The answer you would get is: (0.625) + (0.222)
The final answer is: 0.847

8 0
3 years ago
The standard deviation for actuary salaries has a standard deviation of $36,730 . You collect a simple random sample of n=36 sal
Yanka [14]

Using the z-distribution, it is found that the lower limit of the 95% confidence interval is of $99,002.

<h3>What is a z-distribution confidence interval?</h3>

The confidence interval is:

\overline{x} \pm z\frac{\sigma}{\sqrt{n}}

In which:

  • \overline{x} is the sample mean.
  • z is the critical value.
  • n is the sample size.
  • \sigma is the standard deviation for the population.

In this problem, we have a 95% confidence level, hence\alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so the critical value is z = 1.96.

The other parameters are given as follows:

\overline{x} = 111000, \sigma = 36730, n = 36

Hence, the lower bound of the interval is:

\overline{x} - z\frac{\sigma}{\sqrt{n}} = 111000 - 1.96\frac{36730}{\sqrt{36}} = 99002

The lower limit of the 95% confidence interval is of $99,002.

More can be learned about the z-distribution at brainly.com/question/25890103

#SPJ1

8 0
2 years ago
Which ordered pair would form a proportional relationship with the point graphed below?
Serhud [2]

40,20

hope this helps :)

6 0
3 years ago
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