Help me out and explain in how to do it I'll mark brainlist if you explain how do you solve this problem.
1 answer:
You might be interested in
This ones a bit of a trick question, since whether the integers are even or odd doesn't really matter. What does matter, is that consecutive odd integers are 2 numbers apart (as are consecutive even integers).
So again, if the first of the odd integers is the variable n
the consecutive odd integers after it can be written as:
n+2 , n+4, etc...
So the sum of four consecutive odd integers can be written as:
sum = n + (n+2) + (n+4) + (n+6)
Simplify:
sum = 4n + 12
And finally rearrange to solve for n:
= n
This can also be written as:
- 3 = n
Whichever way you prefer.
You need to implement the process of "flip-flop" and multiply which is where you flip the second fraction and multiply.
÷
⇒×
Now you multiply across. 2×15=30 and 3×11=33
So now it is
-----------------------------------------------------------
To reduce to the lowest terms, find the GCF common factor
The GCF is 3
Divide both the numerator and denominator by 3
÷
=
Answer:
Now you multiply across. 2×15=30 and 3×11=33
So now it is
-----------------------------------------------------------
To reduce to the lowest terms, find the GCF common factor
The GCF is 3
Divide both the numerator and denominator by 3
Answer: