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tino4ka555 [31]
3 years ago
15

Please help on this one?

Mathematics
2 answers:
Contact [7]3 years ago
8 0

The answer to the problem is A.

sweet-ann [11.9K]3 years ago
4 0
X = 5y - 19
x + 19 = 5y
(x + 19)/5 = y
The answer is A.
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An engineer wishes to determine the width of a particular electronic component. If she knows that the standard deviation is 1.6
nexus9112 [7]

Answer:

n=1705

Step-by-step explanation:

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Assuming the X follows a normal distribution  

X \sim N(\mu, \sigma=1.6)  

And the distribution for \bar X is:

\bar X \sim N(\mu, \frac{1.6}{\sqrt{n}})  

We know that the margin of error for a confidence interval is given by:  

Me=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)  

The next step would be find the value of \z_{\alpha/2}, \alpha=1-0.99=0.01 and \alpha/2=0.005  

Using the normal standard table, excel or a calculator we see that:  

z_{\alpha/2}=\pm 2.58  

If we solve for n from formula (1) we got:  

\sqrt{n}=\frac{z_{\alpha/2} \sigma}{Me}  

n=(\frac{z_{\alpha/2} \sigma}{Me})^2  

And we have everything to replace into the formula:  

n=(\frac{2.58(1.6)}{0.1})^2 =1704.03  

And if we round up the answer we see that the value of n to ensure the margin of error required \pm=0.1 mm is n=1705.  

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3 years ago
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B undefined it is not constent
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3 years ago
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