Answer: Blindly selecting from a bag filled with blue green red and yellow beads.
Explanation: I looked around on brainly and other websites since you did not provide the choices and I found out this answer. Let me know if it helped!
<span>The student who use the hemoglobin data to conclude that mice and shrews are more closely related than mice and humans or shrew and human is quite correct. Scientists had found a way of determining the evolution histroy of animals by means of the amino acid sequence of their hemoglobin. The higher the number of related amino acids found the closer the relationship between the two organisms. There are a difference of 29 amino acid between man and mouse and a difference of 24 amino acids between human and shrew but only a difference of 5 amino acid between mouse and shrew. This shows that mouse and shrew are closer.</span>
Answer:
The best way to find out if the amoeba and paramecium are alive is to look at them under the microscope and see them moving. The E coli and Bacillus you can spread on nutrient agar in a Petri dish and see if they form colonies.
Explanation:
When a warm air mass is caught between two colder air masses - cool temperatures and large amounts of rain or snow. When a cold air mass meets a warm air mass and remain separated. Brings<span> many days of cloudy, wet </span>weather<span>. ... </span>Brings dry<span>, </span>clear weather<span>.</span>
42% of rabbits in the population are heterozygous for the mutant Sp1 allele
Hardy-Weinberg equilibrium
- Assume that p is the frequency of the dominant allele
- p² is the frequency of the organisms with homozygous dominant genotype
- Assume that q is the frequency of the recessive allele
- q² is the frequency of the organisms with homozygous recessive genotype
- 2pq is the frequency of the organisms with heterozygous genotype
- p+q = 1
According to the question, 900 out of 10000 rabbits are homozygous recessive
- This implies that q² = 900/10000= 9/100= 0.09
- So, q = 0.3
- The frequency of the recessive allele is 0.3
- p = 1-q = 1-0.3= 0.7
For organisms with heterogenous genotype, their frequency is 2pq
2pq= 2 x 0.3 x 0.7 = 0.42
In terms of percentage, 0.42x 100% = 42%
Therefore, 42% of rabbits in the population are heterozygous for the mutant Sp1 allele.
Learn more about Hardy-Weinberg equilibrium here:
brainly.com/question/10482905
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