3/11 divided by 9/13 = 3/11 multiplied by 13/9 = 39/99=13/33
It is even! hope this helps!
Answer: y = -2/3(x-3)^2 + 0 or y = -2/3(x-3)^2
Step-by-step explanation:
vertex form is y=a(x-h)^2 + k
here we can see the vertex is (3,0) which is (x,y). Or (h,k) in this case.
so to plug that into vertex form, we now have y=a(x-3)^2 + 0. or just y=a(x-3)^2.
now we need to find "a" which is the leading coefficient. to do that we can plug in the (6,-6) for the x and y parts of the above equation. so we'd have
-6=a(6-3)^2. which goes to -6=a(2)^2 which is -6=4a. divide each side by 4 to get a = -2/3. plug this in for a
the final equation would be y = -2/3(x-3)^2 + 0 or y = -2/3(x-3)^2
Answer:
c = 2.25
Step-by-step explanation:
f(x) is a continuous and differentiable function on the interval, so the Mean Value Theorem guarantees a value for c exists.
The average slope is ...
m = (f(4) -f(1))/(4 -1) = (24 -12)/3 = 4
The point at which the derivative is 4 is ...
f'(c) = 6/√c = 4
√c = 6/4
c = 2.25
