Since, the boiling point of jet fuel = 329 °F
We have to convert the boiling point of jet fuel in 
.
The expression which is used to convert 
to is given by:
C = 
= 
= 
= 165
Therefore, the boiling point of jet fuel is 165 .
Answer:
Step-by-step explanation:
circumference is 2πr
r=d/2
r=4.46m
C=2π(4.46)=28.02
Answer:
ice cream = 3.80$
cup cake = 4.25$
donuts = 2.5$
Step-by-step explanation:
a=ice cream
b = cup cake
c = donuts
we can write the following equations given from the picture:
a+b+b=12.30$ equation 1
b+c+a=10.55$ equation 2
b+c+c =9.25$ equation 3
using equation 1 we have:
2b+a=12.30
a=12.30-2b
using equation 3 we have:
2c+b=9.25
c=(9.25-b)/2
using equation 2 we have:
b+((9.25-b)/2)+12.30-2b=10.55
((2b+9.25-b)/2) - 2b = 10.55-12.30
((2b+9.25-b-4b)/2) =-1.75
-3b+9.25=2*(-1.75)
-3b= -3.5-9.25
-3b=-12.75
b=12.75/3
so we have b= 4.25$ = cup cake
we have:
c=(9.25-b)/2= (9.25-4.25)/2
c=2.5$= donuts
a= 12.30-2b= 12.30-2*(4.25)
a= 12.30-8.5 = 3.8$ = ice cream
