Short answer
For 6: 72 ft^2
For 7: 650 m^2
Six
The base is a square. It's measurement is s = 4
Base = 4^2
Base = 16 ft^2
One triangle
A = 1/2 * b * h
A = 1/2 * 4 * 7
A = 14 tt^2
Four triangles
A = 4 * 14
A = 56 ft^2
Total Area = 56 + 16 = 72 ft^2
Answer 72 square feet
Seven
Triangles
Area of 1 triangle = 1/2 * 10 * 13
Area of 1 triangle = 65
Area of 6 triangles
Area of 6 triangles = 6 * area of 1 triangle
Area of 6 triangles = 390
Base
As near as I can tell, the base is a hexagon. It's using a rather out of the way method of drawing it. I will assume it is a regular hexagon. The area of a regular hexagon is 3 sqrt(3)/2 * S^2 where s is the side of the hexagon.
Area = 3sqrt(3)/2 s^2
s = 10
Area = 3sqrt(3)/2 10^2
Area = 5.1962 * 100 /2
Area = 259.81
Total area
Total area = area of the base + area of the triangles
Total area = 259.81 + 390
Total area (rounded ) = 650
Answer C <<<< answer
I'll do one more in this batch and then you'll need to repost again.
Eight
If you draw two diagonals on the base of the figure, the intersection point will meet the base of the height. Read that a couple of times.
Join the intersection to the midpoint of the length of the square bottom. You should get 3.5
x is found by using the pythagorean theorem.
h = 6
s = 3.5
x = ????
x^2 = 6^2 + 3.5^2
x^2 = 36 + 12.25
x^2 = 48.25
x = sqrt(48.25)
x = 6.95
C <<<< answer
Answer:
Parabolas are frequently used in physics and engineering for things such as the design of automobile headlight reflectors and the paths of ballistic missiles. Parabolas are frequently encountered as graphs of quadratic functions.
Answer:
Volume is 
Solution:
As per the question:
Diameter, d = 40 m
Radius, r = 20 m
Now,
From north to south, we consider this vertical distance as 'y' and height, h varies linearly as a function of y:
iff
h(y) = cy + d
Then
when y = 1 m
h(- 20) = 1 m
1 = c.(- 20) + d = - 20c + d (1)
when y = 9 m
h(20) = 9 m
9 = c.20 + d = 20c + d (2)
Adding eqn (1) and (2)
d = 5 m
Using d = 5 in eqn (2), we get:
Therefore,
Now, the Volume of the pool is given by:
where
A = 
Thus
![V = [- 533.33cos\theta + 1000\theta]_{0}^{2\pi}](https://tex.z-dn.net/?f=V%20%3D%20%5B-%20533.33cos%5Ctheta%20%2B%201000%5Ctheta%5D_%7B0%7D%5E%7B2%5Cpi%7D)
Answer:
The answer is: y = 2/3x - 3
Step-by-step explanation:
Given point: (3, -1)
Given equation: y = 2/3x - 5, which is in the form y = mx + b where m is the slope and b is the y intercept.
Parallel lines have the same slope. Use the point slope form of the equation with the point (3, -1) and substitute:
y - y1 = m(x - x1)
y - (-1) = 2/3(x - 3)
y + 1 = 2/3x - 6/3
y + 1 = 2/3x - 2
y = 2/3x - 3
Proof:
f(3) = 2/3(3) - 3
= 6/3 - 3
= 2 - 3
= -1, giving the point (3, -1)
Hope this helps! Have an Awesome Day!! :-)
8 balls = 16
1 ball = 2
32 balls = 64
