Answer:
since 0=noon
and 15 secs=25% of a min
plot the point on the very first line to the right of 0
(the tiny line)
Step-by-step explanation:
The length of segment BC can be determined using the distance formula, wherein, d = sqrt[(X_2 - X_1)^2 + (Y_2 - Y_1)^2]. The variable d represent the distance between the two points while X_1, Y_1 and X_2, Y_2 represent points 1 and 2, respectively. Plugging in the coordinates of the points B(-3,-2) and C(0,2) into the equation, we get the length of segment BC equal to 5.
The length and width that will maximize the area are 175 ft and 87.5 ft respectively
The largest area that can be enclosed is 15312.5 ft²
<h3>Area of a rectangle</h3>
where
l = length
w = width
The fencing is 350 ft it is use to enclose a rectangular plot with a river occupying one part.
Therefore,
perimeter = l + 2w
350 = l + 2w
l = 350 - 2w
area = (350 - 2w)w
(350 - 2w)w = 0
where
w = 0 or 175
average = 175/2 = 87.5
Hence, the max area is at w = 87.5 ft
Therefore,
l = 350 - 2(87.5) = 175 ft
length = 175 ft
width = 87.5 ft
Therefore,
area = 175 × 87.5 = 15312.5 ft²
Therefore, the largest area that can be enclosed is 15312.5 ft²
learn more on rectangle here: brainly.com/question/11630499
Step-by-step explanation:
step 1. an example of difference of squares (dos) is (x + y)(x - y) = x^2 - y^2.
step 2. dos must have only 2 square rootable terms and a "-" between them.
step 3. 196x^2 - 121y^2 = (14x + 11y)(14x - 11y) works!
step 4. 5x^2 - 245 = 5(x^2 - 49) = 5(x + 7)(x - 7) works!
step 5. 27w^5 - 75w = 3w(9w^4 - 25) = 3w(3w^2 + 5)(3w^2 - 5) works!
step 6. x^4 - 100y^2 = (x^2 - 10y)(x^2 + 10y) works!
Think of absolute value and inverse operation, +72 to 72 and 24
