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LuckyWell [14K]
3 years ago
14

Question 5

Mathematics
1 answer:
geniusboy [140]3 years ago
7 0

Answer:

\frac{4}{9}

Step-by-step explanation:

To find this probability, we have to know:

  • How many numbers are there in between 5 and 8 inclusive?
  • How many total numbers are there?

We simply divide the first answer by the second one and get our probability.

So, the numbers are 5,6,7,8 ----- that is 4 numbers

How many numbers are there in total?  That is:

0, 1, 2, 3, 4, 5, 6, 7, 8, or 9  ------- 9 numbers

Thus, the probability is 4/9

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we know that

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Suppose a simple random sample of size n is drawn from a large population with mean mu and standard deviation sigma. The samplin
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Answer:

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\mu_{\bar X} = \mu

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Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

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Solution to the problem

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

X \sim N(\mu,\sigma)  

Where \mu the mean and \sigma  the deviation

Since the distribution for X is normal then we can conclude that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

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