Estimate the measure of the clockwise angle formed by the minute hand and the second hand, then classify the angle.

Naddik [55]

You use the FOIL method, and how you do this is -

(x - 7) (x + 8)

Multiply the first x by both numbers in the second factor. Which means, you multiply x by x and 8, the two in (x + 8).

With this, you get -
x^2 + 8x

Then do the same thing with -7.

-7x - 56

Then combine the two.
x^2 + 8x - 7x - 56

Combine like terms.

x^2 + x - 56

So now, 7 x 8 is 56
And -7 + 8 would be 1. And that is the value of “x” which is b in the form a^2x + bx + c.

Now with this, you take those two numbers and make the factors =
(x + 8) (x - 7)

Then you set these equal to 0.

x + 8 = 0

Subtract the 8 from both sides.

x = -8

————

x - 7 = 0

Add the 7 on both sides.

x = 7

Answer: A

8 0

3 years ago

Read 2 more answers

Zappos is an online retailer based in Nevada and employs 1,300 employees. One of their competitors, Amazon, would like to test t

Amanda [17]

Answer:

$t=\frac{33.9-36}{\frac{4.1}{\sqrt{22}}}=-2.402$

$df = n-1= 22-1=21$

$t_{\alpha/2}= -2.08$

Since the calculated values is lower than the critical value we have enough evidence to reject the null hypothesis at the significance level of 2.5% and we can say that the true mean is lower than 36 years old

Step-by-step explanation:

Data given

$\bar X=33.9$ represent the sample mean

$s=4.1$ represent the sample standard deviation

$n=22$ sample size

$\mu_o =26$ represent the value that we want to test

$\alpha=0.025$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

System of hypothesis

We need to conduct a hypothesis in order to check if the true mean is less than 36 years old, the system of hypothesis would be:

Null hypothesis: $\mu \geq 36$

Alternative hypothesis: $\mu < 36$

The statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

And replacing we got:

$t=\frac{33.9-36}{\frac{4.1}{\sqrt{22}}}=-2.402$

Now we can calculate the critical value but first we need to find the degreed of freedom:

$df = n-1= 22-1=21$

So we need to find a critical value in the t distribution with df =21 who accumulates 0.025 of the area in the left and we got:

$t_{\alpha/2}= -2.08$

Since the calculated values is lower than the critical value we have enough evidence to reject the null hypothesis at the significance level of 2.5% and we can say that the true mean is lower than 36 years old

3 0

3 years ago

Need answer quick. No need for big explanantion

Leona [35]

Answer:

Step-by-step explanation:

4.30/40=$0.1075

Hope this helps :)

5 0

3 years ago

WILL MARK BRAINIEST!!!

Zarrin [17]