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Nady [450]
3 years ago
7

Estimate the measure of the clockwise angle formed by the minute hand and the second hand, then classify the angle.

Mathematics
1 answer:
irga5000 [103]3 years ago
8 0
<span>A. 54°; acute is the answer</span>
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Am getting the hang of this but I still need help so may I please get help with this equation -7a+6a^2-10
blagie [28]
The factors are (a - 2) and (6a + 5) . If the expression is equal to zero, then 'a' can be 2, and 'a' can be -5/6 .
7 0
3 years ago
Read 2 more answers
PLEASSE HELP URGENT WILL GIVE BRAINLIEST FOR CORRECT ANSWER Brian wanted to find out if studying for the algebra test is effecti
Viefleur [7K]

Answer:

2/130 or 1/65

Step-by-step explanation:

64+4+2+60 (all the people) =130

Given the fact that ''2 learners studied but failed the test.'' Brian is the same.

So you would do 2/130 or simplify it, 1/65.

Hope it helps :)

6 0
3 years ago
Check my answer please?! <br><br> All i did was divide 14.4 by 1/2<br> Am i correct?
aliina [53]
 yes you are correct are you good at counterexample

 
5 0
2 years ago
Write the quadratic equation that has roots -1-rt2/3 and -1+rt2/3 if its coefficient with x^2 is equal to 1
weeeeeb [17]

The equation of the quadratic function is f(x) = x²+ 2/3x - 1/9

<h3>How to determine the quadratic equation?</h3>

From the question, the given parameters are:

Roots = (-1 - √2)/3 and (-1 + √2)/3

The quadratic equation is then calculated as

f(x) = The products of (x - roots)

Substitute the known values in the above equation

So, we have the following equation

f(x) = (x - \frac{-1-\sqrt{2}}{3})(x - \frac{-1+\sqrt{2}}{3})

This gives

f(x) = (x + \frac{1+\sqrt{2}}{3})(x + \frac{1-\sqrt{2}}{3})

Evaluate the products

f(x) = (x^2 + \frac{1+\sqrt{2}}{3}x + \frac{1-\sqrt{2}}{3}x + (\frac{1-\sqrt{2}}{3})(\frac{1+\sqrt{2}}{3})

Evaluate the like terms

f(x) = x^2 + \frac{2}{3}x - \frac{1}{9}

So, we have

f(x) = x²+ 2/3x - 1/9

Read more about quadratic equations at

brainly.com/question/1214333

#SPJ1

7 0
1 year ago
the number of hours,h, it takes to wash c numbers of cars at a school fundraiser is inversely proportional to the number of stud
Alex787 [66]
\bf \qquad \qquad \textit{inverse proportional variation}&#10;\\\\&#10;\textit{\underline{y} varies inversely with \underline{x}}\qquad \qquad  y=\cfrac{k}{x}\impliedby &#10;\begin{array}{llll}&#10;k=constant\ of\\&#10;\qquad  variation&#10;\end{array}\\\\&#10;-------------------------------\\\\&#10;\stackrel{\textit{\underline{h}ours to wash a car, is inversely proportional to \underline{s}tudents working on it}}{h=\cfrac{k}{s}}
3 0
2 years ago
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