All categories

2 years ago

The perimeter of rectangular park is 450m.the length of the sides is in the ratio 3:2.find the area of the rectangle

Mathematics

1 answer:

matrenka [14]2 years ago

6 0

Answer: 12,150 m²

Step-by-step explanation:

The ratio is 3:2 which means

Length (L) = 3x

Width (w) = 2x

Perimeter (P) = 2L + 2w

450 = 2(3x) + 2(2x)

450 = 6x + 4x

450 = 10x

45 = x

L = 3x w = 2x

= 3(45) = 2(45)

= 135 = 90

Area (A) = L × w

= 135 × 90

= 12,150

You might be interested in

PLZ HELP THIS IS DUE TODAY AND NO LINKS PLZ.

anastassius [24]

Answer:

D is the best answer to the question

8 0

2 years ago

How to square imaginary numbers

dalvyx [7]

An imaginary number " i " is the squared root of -1, so whenever you square i it's like squaring a squared root. The squared root would cancel and you would be left with just the number under it, that is, the -1.
i ^ 2 = -1

5 0

3 years ago

Express the probability that a die wil land on a number less than 5 as a fraction

Rashid [163]

Answer:

$\frac{2}{3}$

Step-by-step explanation:

Values less than 5 on a die are 1, 2, 3, 4 ← 4 values out of a possible 6

P( < 5) = $\frac{4}{6}$ = $\frac{2}{3}$ in simplest form

7 0

3 years ago

A researcher claims that the variation in the salaries of elementary school teachers is greater than the variation in the salari

guajiro [1.7K]

Answer:

The null hypothesis is $H_o : \sigma^2_1 = \sigma^2 _2$

The alternative hypothesis is $H_a : \sigma_1 ^2 > \sigma^2_2$

$F_{critical} = 1.8608$

$F = 2.9085$

The decision rule is

Reject the null hypothesis

There is sufficient evidence to support the researchers claim

Step-by-step explanation:

From the question we are told that

The first sample size is $n_1 = 30$

The sample variance for elementary school is $s^2_1 = 8324$

The second sample size is $n_2 = 30$

The sample variance for the secondary school is $s^2_2 = 2862$

The significance level is $\alpha = 0.05$

The null hypothesis is $H_o : \sigma^2_1 = \sigma^2 _2$

The alternative hypothesis is $H_a : \sigma_1 ^2 > \sigma^2_2$

Generally from the F statistics table the critical value of $\alpha = 0.05$ at first and second degree of freedom $df_1 = n_1 - 1 = 30 - 1 = 29$ and $df_2 = n_2 - 1 = 30 - 1 = 29$ is

$F_{critical} = 1.8608$

Generally the test statistics is mathematically represented as

$F = \frac{s_1^2 }{s_2^2}$

=> $F = \frac{8324 }{2862}$

=> $F = 2.9085$

Generally from the value obtained we see that $F > F_{critical }$ Hence

The decision rule is

Reject the null hypothesis

The conclusion is

There is sufficient evidence to support the researchers claim

4 0

2 years ago

The mean of a normally distributed dataset is 12, and the standard deviation is 2.

Schach [20]

So lets do it like this:
z = (X-Mean)/SD
z1 = (8-12)/2 = - 2 
z2 = (16-12)/2 = + 2 
According to the Empirical Rule 68-95-99.7 
Mean more or less 2SD covers 95% of the values 
So the percentage of data points falling between 8 and 16 = 95%
I hope this can help

5 0

3 years ago