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2 years ago

Find the equation of the line which passes through to (2,-1) and slope is 3

Mathematics

1 answer:

Veronika [31]2 years ago

6 0

Answer:

The point slope form of the line would be y + 1 = 3(x - 2) and the equation of the line would be y = 3x - 7

Step-by-step explanation:

To find the point-slope form of the line, start with the base form of point-slope form. Then input the point we have and the slope in the appropriate places.

y - y1 = m(x - x1)

y - -1 = 3(x - 2)

y + 1 = 3(x - 2)

Now to find the slope intercept form, you simply need to solve for y.

y + 1 = 3(x - 2)

y + 1 = 3x - 6

y = 3x - 7

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There are 25 scented candles left in stock on eBay. On amazon there are 12 + (9x3) scented candles left. How many scented candle

oksano4ka [1.4K]

(9x3)= 27 +12= 39. 39 is the answer

4 0

3 years ago

et mA = 40°. If B is a complement of A, and C is a supplement of B, find these measures. mB = ° mC = °

Free_Kalibri [48]

Alright, lets get started.

We have given angle A = 40°

We are also given angle B is complement of A.

Complementary angles are two angles whose sum is 90, it means

angle B = $90- A$

angle B = $90 - 40$

angle B = 50° Answer

Now given, angle C is supplement of angle B.

Supplementary angles are two angles whose sum is 180°.

Means angle C = $180 - B$

angle C = $180 - 50$

angle C = 130° : Answer

Means angle B = 50° and angle C = 130°

Hope it will help :)

5 0

3 years ago

can someone plz help me on this plz I beg u

STALIN [3.7K]

Answer:

option A is the correct answer

6 0

3 years ago

Read 2 more answers

Name/ Uid:1. In this problem, try to write the equations of the given surface in the specified coordinates.(a) Write an equation

Gemiola [76]

To find:

(a) Equation for the sphere of radius 5 centered at the origin in cylindrical coordinates

(b) Equation for a cylinder of radius 1 centered at the origin and running parallel to the z-axis in spherical coordinates

Solution:

(a) The equation of a sphere with center at (a, b, c) & having a radius 'p' is given in cartesian coordinates as:

$(x-a)^{2}+(y-b)^{2}+(z-c)^{2}=p^{2}$

Here, it is given that the center of the sphere is at origin, i.e., at (0,0,0) & radius of the sphere is 5. That is, here we have,

$a=b=c=0,p=5$

That is, the equation of the sphere in cartesian coordinates is,

$(x-0)^{2}+(y-0)^{2}+(z-0)^{2}=5^{2}$

$\Rightarrow x^{2}+y^{2}+z^{2}=25$

Now, the cylindrical coordinate system is represented by $(r, \theta,z)$

The relation between cartesian and cylindrical coordinates is given by,

$x=rcos\theta,y=rsin\theta,z=z$

$r^{2}=x^{2}+y^{2},tan\theta=\frac{y}{x},z=z$

Thus, the obtained equation of the sphere in cartesian coordinates can be rewritten in cylindrical coordinates as,

$r^{2}+z^{2}=25$

This is the required equation of the given sphere in cylindrical coordinates.

(b) A cylinder is defined by the circle that gives the top and bottom faces or alternatively, the cross section, & it's axis. A cylinder running parallel to the z-axis has an axis that is parallel to the z-axis. The equation of such a cylinder is given by the equation of the circle of cross-section with the assumption that a point in 3 dimension lying on the cylinder has 'x' & 'y' values satisfying the equation of the circle & that 'z' can be any value.

That is, in cartesian coordinates, the equation of a cylinder running parallel to the z-axis having radius 'p' with center at (a, b) is given by,

$(x-a)^{2}+(y-b)^{2}=p^{2}$

Here, it is given that the center is at origin & radius is 1. That is, here, we have, $a=b=0,p=1$ . Then the equation of the cylinder in cartesian coordinates is,

$x^{2}+y^{2}=1$

Now, the spherical coordinate system is represented by $(\rho,\theta,\phi)$

The relation between cartesian and spherical coordinates is given by,

$x=\rho sin\phi cos\theta,y=\rho sin\phi sin\theta, z= \rho cos\phi$

Thus, the equation of the cylinder can be rewritten in spherical coordinates as,

$(\rho sin\phi cos\theta)^{2}+(\rho sin\phi sin\theta)^{2}=1$

$\Rightarrow \rho^{2} sin^{2}\phi cos^{2}\theta+\rho^{2} sin^{2}\phi sin^{2}\theta=1$

$\Rightarrow \rho^{2} sin^{2}\phi (cos^{2}\theta+sin^{2}\theta)=1$

$\Rightarrow \rho^{2} sin^{2}\phi=1$ (As $sin^{2}\theta+cos^{2}\theta=1$ )

Note that $\rho$ represents the distance of a point from the origin, which is always positive. $\phi$ represents the angle made by the line segment joining the point with z-axis. The range of $\phi$ is given as $0\leq \phi\leq \pi$ . We know that in this range the sine function is positive. Thus, we can say that $sin\phi$ is always positive.

Thus, we can square root both sides and only consider the positive root as,

$\Rightarrow \rho sin\phi=1$

This is the required equation of the cylinder in spherical coordinates.

Final answer:

(a) The equation of the given sphere in cylindrical coordinates is $r^{2}+z^{2}=25$

(b) The equation of the given cylinder in spherical coordinates is $\rho sin\phi=1$

7 0

2 years ago

Two trucks leave a warehouse at the same time. One travels due east at an average speed of 50 miles per hour, and the other trav

Keith_Richards [23]

Answer:Since the vehicles are travelling in the exact opposite direction, the sum of their rates is the rate at which they are separating. 48 + 64 = 112 miles per hour of separation.

728 miles ÷ 112 miles/hour = 6.5 hours

Step-by-step explanation:

8 0

2 years ago