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Mekhanik [1.2K]
3 years ago
8

Find four consecutive multiples of 5 whose sum is 90

Mathematics
1 answer:
Umnica [9.8K]3 years ago
3 0
M₅+(M₅+5)+(M₅+10)+(M₅+15)=90

5M₅+ 30=90

5M₅=90-30

5M₅=60

M₅=60:5

M₅=12

M₅+5=12+5=17

M₅+10=12+10=22

M₅+15=12+15=27
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Step-by-step explanation:

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