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KatRina [158]
3 years ago
11

What number must be added to the expression below to complete the square? x² - 18x

Mathematics
1 answer:
kiruha [24]3 years ago
5 0

Answer:

\boxed {\boxed {\sf 81}}

Step-by-step explanation:

The standard form of a quadratic is:

ax^2+bx+c

To complete the square, the a (leading coefficient) must be 1 and there can only be terms with variables on one side.

The expression given:

x^2-18x

follows these rules. Next, we divide the b (linear coefficient) by 2, then square it. Basically:

(\frac{b}{2})^2

The b in the expression is -18.

(\frac{-18}{2})^2

(-9)^2= -9*-9= 81

This is the number that is added.

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Find the value of $x$ for the right triangle. A right triangle with base labeled x and hypotenuse labeled 12 units. Angle betwee
slamgirl [31]

Answer:

6 feets

Step-by-step explanation:

The triangle described in the question has been sketched in the picture attached below :

From the triangle, we could solve for X, which is the base of the triangle using trigonometry :

Sinθ = opposite / hypotenus

Sin 30° = x / 12

0.5 = x / 12

x = 12 * 0.5

x = 6 feets

Hence base, x = 6 feets

8 0
3 years ago
Help me plz and thx :)
ikadub [295]

Answer:

I am sure it is false. becuase a dependent variable is something you measure and you have to count the eggs.

4 0
2 years ago
Can somebody please give me the answer I will mark u brilliant
VARVARA [1.3K]

Answer:

x = 6.7

Step-by-step explanation:

We know that 3.5 + x = 10.2, so if we do inverse operations we can find out the value of x.

10.2 - 3.5 = 6.7

we can check our work by substituing it back in the equation for x

6.7 + 3.5 = 10.2

so now we know that x = 6.7. I hope this helps :)

7 0
3 years ago
Read 2 more answers
Find sum or difference.<br><br>-1/2 + 1/3
Free_Kalibri [48]
2/5 is the answer unless your multiplying
6 0
2 years ago
Polynomial function in standard form with zeros 5,-4,1
Oksanka [162]

Answer:

\boxed{\sf \ \ \  x^3-2x^2-19x+20 \ \ \  }

Step-by-step explanation:

hello,

by definition we can write

(x-5)(x+4)(x-1)

as 5,-4,1 are the zeroes

now we have to write it in the standard form, let's do it

(x-5)(x+4)(x-1)=(x^2+4x-5x-20)(x-1)\\=(x^2-x-20)(x-1)=x^3-x^2-20x-x^2+x+20\\=x^3-2x^2-19x+20

hope this helps

5 0
3 years ago
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