V^2/(1-v^2/c^2)=R
v^2=R(1-v^2/c^2)
v^2=R-Rv^2/c^2
v^2-Rv^2/c^2=R
v^2(1-R/c^2)=R
v=sqrt(R/(1-R/c^2))
where R was original right side, dont forget plus minus
Answer:
36.4mi
Step-by-step explanation:
The boat sailed two legs of a right-angled triangle.
The distance from the starting point is the hypotenuse of the triangle.
d = √(35² + 10²)
= √(1225 + 100)
= √1325
= 36.4 mi
Multiply using the distributive property so it would be 5x+60