he graph of the equation y = 2x2 - 2 is shown. Which equation will shift the graph up 3 units? A) y = 2x2 B) y = 2x2 +1 C) y = 2
1 answer:
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Answer:
5x -7y = 21
Step-by-step explanation:
A sketch can convince you that BC is a transversal perpendicular to parallel lines AB and CD. The question asks for an equation for CD, so we just need to write the equation of a line through D that is parallel to AB.
One way to do this is to equate the slopes of the parallel lines:
∆y/∆x for AB = ∆y/∆x for CD
(y2 -y1)/(x2 -x1) = (y -2)/(x -7) . . . . . . where (x1, y1) = A; (x2, y2) = B; (7, 2) = D
(4 -(-1))/(1 -(-6)) = (y -2)/(x -7)
5(x -7) = 7(y -2) . . . . . . . . . . . . . cross multiply
5x -7y = 21 . . . . . . . . . . . . . . . . add 35 -7y, simplify
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Note that the graph shows the line CD is named "b", and its equation is shown at upper left. Multiplying that equation by -1 gives the one shown here.
The completely factored equation is (a²b - 5)(4a²b - 1)
<h3>How to factor equation?</h3>4a⁴b² - 21a²b + 5 = 0
let's expand the equation
Therefore,
4a⁴b² - 21a²b + 5 = 0
4a⁴b² - 20a²b - a²b + 5 = 0
Rearrange the equation
4a⁴b² - a²b - 20a²b + 5 = 0
Let's factorise the equation
4a⁴b² - a²b - 20a²b + 5 = 0
a²b(4a²b - 1) - 5(4a²b - 1) = 0
Therefore, the completely factored equation is as follows:
a²b(4a²b - 1) - 5(4a²b - 1) = 0
(a²b - 5)(4a²b - 1)
learn more on equation here: brainly.com/question/8842252
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