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nydimaria [60]
3 years ago
11

Kevin won to gold fish a the county fair he put them in a bowl that hold 2 liters of water the next day he put them in a bowl th

at holds 75 leters of water the gold fish look happy
Mathematics
1 answer:
zlopas [31]3 years ago
6 0

Thats cool but where question

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Which best describes a transformation that preserves the size, shape, and angles of an object?
vovikov84 [41]
The transformation is ISOMETRY.

In mathematics, an isometry<span> (or congruence, or congruent transformation) is a distance-preserving transformation between metric spaces, usually assumed to be bijective. A composition of two opposite </span>isometries<span> is a direct </span>isometry<span>. A reflection in a line is an opposite </span>isometry<span>, like R </span>1<span> or R </span>2<span> on the image.</span>
3 0
3 years ago
The midpoint of PQ is M(2,-3). One endpoint is<br> P(4,1). Find the coordinates of endpoint Q.
kupik [55]
Q (0,-7)

Hope this helps
3 0
3 years ago
Which angles are complementary to each other?
ollegr [7]

complementary angles are angles that, when added together, make 90 degrees.

3 0
3 years ago
Can someone help me ? i have no clue how to figure this out
Ad libitum [116K]

\cos t (\sec t - \cos t) = \sin^2 t

\cos t (\dfrac{1}{\cos t} - \cos t) = \sin^2 t

\dfrac{\cos t}{\cos t} - \cos^2 t = \sin^2 t

1 - \cos^2 t = \sin^2 t

Use the identity: \sin^2 t + \cos^2 t = 1 and solve for \sin^2 t. You get: \sin^2 t = 1 - \cos^2 t

Do the substitution on the left side to get:

\sin^2 t = \sin ^2 t

5 0
2 years ago
Read 2 more answers
an angle bisector of a triangle divides the opposite side of the triangle into segments 6 cm and 5cm long. A second side of the
rodikova [14]
There is a not so well-known theorem that solves this problem.

The theorem is stated as follows:
"Each angle bisector of a triangle divides the opposite side into segments proportional in length to the adjacent sides"  (Coxeter & Greitzer)

This means that for a triangle ABC, where angle A has a bisector AD such that D is on the side BC, then 
BD/DC=AB/AC

Here either
BD/DC=6/5=AB/AC, where  AB=6.9,  
then we solve for  AC=AB*5/6=5.75,

or

BD/DC=6/5=AB/AC, where  AC=6.9,  
then we solve for AB=AC*6/5=8.28

Hence, the longest and shortest possible lengths of the third side are
8.28 and 5.75 units respectively.

4 0
3 years ago
Read 2 more answers
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