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nydimaria [60]
3 years ago
11

Kevin won to gold fish a the county fair he put them in a bowl that hold 2 liters of water the next day he put them in a bowl th

at holds 75 leters of water the gold fish look happy
Mathematics
1 answer:
zlopas [31]3 years ago
6 0

Thats cool but where question

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The speed of light is 3.0 x 10^8 m / s The sun is approximately 230,000,000,000 meters from Mars. How many seconds does it take
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Answer:




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5 0
2 years ago
Jon loves to go bird watching at a nearby animal sanctuary. Find the mean of the following numbers of birds he spotted at the sa
DIA [1.3K]

Answer:

Mean = 12

Step-by-step explanation:

The arithmetic mean of a distribution is the sum of the number of samples in the distribution divided by the number of samples in the dataset. It is a measure of central tendency. The mean is represented as follows:

\bar x = \frac{\sum x}{n} \\where\\\bar x = mean\\\sum x = sum\ of\ individual\ terms\\n = number\ of\ terms\\\therefore \bar x = \frac{14\ +\ 10\ +\ 17\ +\ 11\ +\ 9\ +\ 15\ +\ 6\ +\ 14}{8}\\\bar x = \frac{96}{8} \\\bar x = 12

Mean = 12

6 0
3 years ago
Write the equation of the line passing through the points (15,3) and (-3, -3).​
sergey [27]

Answer:

#CarryonLearning

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3 0
3 years ago
Read 2 more answers
3 (a) A random sample of 200 voters in a town is selected, and 114 are found to support an annexation suit. Find the 96% confide
hammer [34]

Answer:

a. 0.498 < p < 0.642

b. We are 96% sure that the error of estimator ^p = 0.57 will not exceed 0.07001

Step-by-step explanation:

Given;

Sample, n = 200 voters

Let x represent those that support annexation suit.

x = 114

First, we'll calculate the probability of supporting annexation suit.

Let p represent the probability of supporting annexation suit.

p = x/n

p = 114/200

p = 0.57

From elementary probability;

p + q = 1 where q represent probability of failure.

In this case, q represent probability of not supporting annexation suit

Substitute 0.57 for p

0.57 + q = 1

q = 1 - 0.57

q = 0.43

To find the 96% confidence interval for the fraction of the voting population favoring the suit;

The confidence interval is bounded by the following;

^p - z(α/2) √(pq/n) < p < ^p + z(α/2) √(pq/n)

At this point, we have values for p,q and n.

Next is to solve z(α/2)

First, we'll find the value of α/2 using

C.I = 100%(1 - α) where C.I = 96%

96% = 100%(1 - α)

1 - α = 96%

1 - α = 0.96

α = 1 - 0.96

α = 0.04

So,

α/2 = 0.04/2

α/2 = 0.02

So, z(α/2) = z(0.02)

Using normal probability table

z0.02 = 2.055 --- This is the closest value which leaves an area of 0.02 to the right and 0.98 to the left

Recalling our formula to solve 96% interval;

^p - z(α/2) √(pq/n) < p < ^p + z(α/2) √(pq/n)

By substituton, we have

0.57 - 2.055 * √(0.57*0.43/200) < p < 0.57 + 2.055 * √(0.57*0.43/200)

0.57 - 0.071939677073920 < p < 0.57 + 0.071939677073920

0.498060322926079 < p < 0.641939677073920 ---- Approximate

0.498 < p < 0.642

b. Here, we'll make use of the following theorem;

Using ^p as an estimate

We are 100%(1 - α) confident that the error will not exceed z(α/2) √(pq/n)

From (a), we have.

z(α/2) = 2.055, p = 0.57, q = 0.43, n = 200

By substituton, z(α/2) √(pq/n) becomes

2.055 * √(0.57 * 0.43/200)

= 2.055 * 0.071939677073920

= 0.070014284256857 ---- Approximate

= 0.07001

We are 96% sure that the error of estimator ^p = 0.57 will not exceed 0.07001

7 0
3 years ago
HELP PLEASE<br><br> Simplify the expression where possible. (-5x 2) 3
abruzzese [7]

Answer:

(-5x2)•3=

-15x^2

3 0
3 years ago
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