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1 year ago

Which is the completely factored form of the following equation? 4a4b2−21a2b+5=0

Mathematics

1 answer:

r-ruslan [8.4K]1 year ago

4 0

The completely factored equation is (a²b - 5)(4a²b - 1)

<h3>How to factor equation?</h3>

4a⁴b² - 21a²b + 5 = 0

let's expand the equation

Therefore,

4a⁴b² - 21a²b + 5 = 0

4a⁴b² - 20a²b - a²b + 5 = 0

Rearrange the equation

4a⁴b² - a²b - 20a²b + 5 = 0

Let's factorise the equation

4a⁴b² - a²b - 20a²b + 5 = 0

a²b(4a²b - 1) - 5(4a²b - 1) = 0

Therefore, the completely factored equation is as follows:

a²b(4a²b - 1) - 5(4a²b - 1) = 0

(a²b - 5)(4a²b - 1)

learn more on equation here: brainly.com/question/8842252

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