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ELEN [110]
4 years ago
9

What is the GCF of the 48and16

Mathematics
2 answers:
zavuch27 [327]4 years ago
6 0
The GCF would be 16.
rjkz [21]4 years ago
4 0
The greatest common factor of 48 and 16 should be 16
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100 textbooks increased by 99%
nordsb [41]
199. 

99% of 100 is 99. 100 + 99 = 199.
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4 years ago
Solve the equation 7 − 2x = 19.
Karolina [17]

Answer:

-6

Step-by-step explanation:

firstly arrange whole equation,

-2x+7=19

Now, Transpose 7 to RHS (right hand side)

-2x=19-7

-2x=12

Further, seperate coefficient -2 from x

and transpose it to RHS and divide them

x=12/-2

Hence, x= -6

8 0
3 years ago
Select from the drop-down menus to correctly complete the statement.
Sergio [31]

Answer:

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Step-by-step explanation:

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6 0
2 years ago
Which algebraic expression represents “the product of a number and five”?
kirza4 [7]

Answer: n-5

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%5Cfrac%7B%5Csec%5Cleft%28x%5Cright%29%7D%7B%5Ccos%5Cleft%28x%5Cright%29%7D-%5Cfrac%7B%5Csin%5
DanielleElmas [232]

Answer:

1

Step-by-step explanation:

First, convert all the secants and cosecants to cosine and sine, respectively. Recall that csc(x)=1/sin(x) and sec(x)=1/cos(x).

Thus:

\frac{sec(x)}{cos(x)} -\frac{sin(x)}{csc(x)cos^2(x)}

=\frac{\frac{1}{cos(x)} }{cos(x)} -\frac{sin(x)}{\frac{1}{sin(x)}cos^2(x) }

Let's do the first part first: (Recall how to divide fractions)

\frac{\frac{1}{cos(x)} }{cos(x)}=\frac{1}{cos(x)} \cdot \frac{1}{cos(x)}=\frac{1}{cos^2(x)}

For the second term:

\frac{sin(x)}{\frac{cos^2(x)}{sin(x)} } =\frac{sin(x)}{1} \cdot\frac{sin(x)}{cos^2(x)}=\frac{sin^2(x)}{cos^2(x)}

So, all together: (same denominator; combine terms)

\frac{1}{cos^2(x)}-\frac{sin^2(x)}{cos^2(x)}=\frac{1-sin^2(x)}{cos^2(x)}

Note the numerator; it can be derived from the Pythagorean Identity:

sin^2(x)+cos^2(x)=1; cos^2(x)=1-sin^2(x)

Thus, we can substitute the numerator:

\frac{1-sin^2(x)}{cos^2(x)}=\frac{cos^2(x)}{cos^2(x)}=1

Everything simplifies to 1.

7 0
3 years ago
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