Y=a(x-1)^2 -17 is the equation of the parabola.
at (0,16), 16=a(0-1)^2 -17. Solve for a = 33.
Equation is then y=33(x-1)^2-17 so when y=0,
(x-1)^2 = 17/33
x-1 = + and - square root of 17/33
x = 1.7177 and 0,2823 as the intercepts
Answer:
x^3+3x^2+4x+5
Step-by-step explanation:
Ok, so what helps me solve this kind of problem is to circle, underline, or box the like terms(the ones with the same exponent and variable). Be sure to note the sign of each term when combining like terms. take it one step at a time, and work downwards starting with the highest exponent. You have -x^3 and +2x^3, which is x^3. Next, you have +2x^2 and +x^2, which is 3x^2. You should write down each of these as you go, so you should now have x^3+3x^2. Then combine the terms with no exponent but with x, which is 5x and -1x, which is +4x. You should have x^3+3x^2+4x now. Lastly, just combine the numbers 1, -1, and 5, which is 5. This gives you an answer of x^3+3x^2+4x+5.
Answer:
answer a because -15/8 is -1.875
2+sq root of 5
and the sum of zeros = 4
other zero =4-(2+sq root of 5)=2-sq root of 5
Answer:
this is questions in class 10ICSE mathematics chapter linear equations
