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Ratling [72]
4 years ago
15

Name the opposite rays: C A T

Mathematics
1 answer:
DENIUS [597]4 years ago
4 0

Answer:

B.

Step-by-step explanation:

How to name a ray:

A ray is part of a line. It has an endpoint and contains all points of the line to one side of the endpoint. To name a ray, use two points on the ray. The first one must always be the endpoint. The second point is any other point on the ray. The arrowhead above the two letters always points to the right.

Option B is correct.

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I need help plsss. im stuck
noname [10]

Answer:

h = 6 cm

Step-by-step explanation:

Volume of cylinder = 54 π cm³

πr²h = 54π

π * 3 * 3 * h = 54π

h = \frac{54 \pi }{\pi *3*3}\\\\h= 6

6 0
3 years ago
How do you turn .33333333 into a fraction
Firlakuza [10]
3/1 i think
-----------------
7 0
3 years ago
Your class earned $120.00 Saturday afternoon by washing cars to raise money for the class trip. This is 1/4 of the money needed
Ilya [14]

Answer:

$360.00

(I hope this was helpful)

5 0
3 years ago
8/x-5 - 9/x-4 = 5/x^2-9x+20
adelina 88 [10]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/2752942

_______________


Solve the equation:

\mathsf{\dfrac{8}{x-5}-\dfrac{9}{x-4}=\dfrac{5}{x^2-9x+20}\qquad\qquad(x\ne 5~and~x\ne 4)}


Reduce the fractions at the left side so that they have the same denominator:

\mathsf{\dfrac{8(x-4)}{(x-5)(x-4)}-\dfrac{9(x-5)}{(x-4)(x-5)}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32}{x^2-4x-5x+20}-\dfrac{9x-45}{x^2-4x-5x+20}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32}{x^2-9x+20}-\dfrac{9x-45}{x^2-9x+20}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32-(9x-45)}{x^2-9x+20}=\dfrac{5}{x^2-9x+20}}


Numerators must be equal:

\mathsf{8x-32-(9x-45)=5}\\\\
\mathsf{8x-32-9x+45=5}\\\\
\mathsf{8x-9x=5+32-45}\\\\
\mathsf{-x=-8}\\\\
\mathsf{x=8}\quad\longleftarrow\quad\textsf{this is the solution.}


I hope this helps. =)


Tags:  <em>rational equation fraction solution algebra</em>

7 0
3 years ago
I need help with 5 and 14 pls
Julli [10]

Answer:

5

(3a²b³c)³(2a⁴b²c²)³

= (3a⁶b⁹c³)(8a¹²b⁶c⁶)

= 24a¹⁸b¹⁵c⁹

14

⁴√(81a¹⁶b¹²c⁹)

= (⁴√81)(⁴√a¹⁶)(⁴√b¹²)(⁴√c⁹)

= 3 (a^{\frac{16}{4} }) (b^{\frac{12}{4} } ) (c^{\frac{9}{4} } )

= 3a^{4} b^{3} c^{\frac{9}{4} }

4 0
3 years ago
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