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Scorpion4ik [409]
4 years ago
4

Figure ABCD is transformed to obtain figure A'B'C'D': A coordinate grid is shown from negative 6 to 6 on both axes at increments

of 1. Figure ABCD has A at ordered pair negative 4, 4, B at negative 2, 2, C at negative 2, negative 1, D at negative 4, 1. Figure A prime B prime C prime D prime has A prime at ordered pair 3, negative 4, B prime at 5, negative 2, C prime at 5, 1, D prime at 3, negative 1. Part A: Write the sequence of transformations that changes figure ABCD to figure A'B'C'D'. Explain your answer and write the coordinates of the figure obtained after each transformation. (6 points)
Mathematics
1 answer:
kakasveta [241]4 years ago
7 0

Answer:

Reflected along x axis

Translated 7 units to the right

Step-by-step explanation:

A transformation of a point is the movement of the point from its initial position to a new position. If an object is transformed, all its points are also transformed. Types of transformation are reflection, rotation, dilation and translation.

Figure ABCD has A at (- 4, 4), B at (- 2, 2), C at (- 2, - 1), D at (- 4, 1).

If a point (x, y) is reflected along the x axis, its x coordinate remains the same and the y coordinate is opposite (negated). The new point is at (x, -y)

If a point (x, y) is translated h units to the right, the new coordinate is (x+h, y).The transformation are as follows:

It is reflected along the x axis so that the new coordinates would be at A1 at (- 4, -4), B1 at (- 2, -2), C1 at (- 2, 1), D1 at (- 4, -1)

It is translated 7 units to the right, The new coordinates are A' at (3, -4), B' at (5, -2), C' at (5, 1), D' at (3, -1)

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4 years ago
Can someone plz help me solve this problem I need help plz someone help me!
cestrela7 [59]

Answer:   25 < P < 36

              15/4 < w < 26/4

              35/4 < L < 46/4

<u>Step-by-step explanation:</u>

Perimeter is BETWEEN 25 and 36

           25 <    P    < 36

Graph:  O--------------O

            25              36

Perimeter = 2L + 2w  ; substitute L = w + 5        

             25 < 2(w + 5) + 2w < 36

             25 < 2w + 10  + 2w < 36

              25 <  4w + 10          < 36

               15 <           4w         < 26

               \dfrac{15}{4} <             w         < \dfrac{26}{4}

              3\dfrac{3}{4}  <              w        <  6\dfrac{1}{2}

Graph:     O------------------------O

              3\dfrac{3}{4}                             6\dfrac{1}{2}

Perimeter = 2L + 2w  ; L = w + 5   --> w = L - 5      

             25 < 2L + 2(L - 5)  < 36

             25 < 2L + 2L  - 10 < 36

              25 <  4L - 10        < 36

              35 <           4L      < 46

              \dfrac{35}{4} <             L       < \dfrac{46}{4}

              8\dfrac{3}{4}  <            L      <  11\dfrac{1}{2}

Graph:     O------------------------O

               8\dfrac{3}{4}                          11\dfrac{1}{2}

Note: Make sure you use OPEN dots when graphing.

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4 years ago
Graph this problem please and thank you
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I am not able to graph but I will help you out. All you have to do to solve this is add the rule to the original x and y values. If the rule is (x+9, y-2) and the point is (-2,3) all we’d to do is plug it in.

-2+9=7
3-2=1
So the new point for P would be (7, 1)

If you need anyone help, lemme know. If you really can’t figure it out. I will grab my computer and graph it for you.
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