Show me number line for 8+x <12

1 answer:

azamat2 years ago

7 0

X < 4

_____________________________
-5 -4 -3 -2 -1 0 1 2 3 4 5 6 7 8

There would be an open circle above the 4 on the number line and then shade everything to the left of it and making sure to include the arrow at the end pointing to the left.

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Select the correct graph of −4x + 3y = 6. (1 point)

mojhsa [17]

Answer:

$Line\ passing\ through\ (-1.5,0)\ and\ (0,2).\\\\Correct\ graph\ is\ attached.$

Step-by-step explanation:

$The\ given\ equation\ represents\ a\ line\\\\$

y-intercept:

$Substitute\ x=0\\\\-4\times 0+3y=6\\\\3y=6\\\\y=\frac{6}{3}\\\\y=2\\\\The\ line\ passes\ through\ the\ point\ (0,2).$

x-intercept:

$Substitute\ y=0\\\\-4x+3\times 0=6\\\\-4x=6\\\\x=-\frac{6}{4}\\\\x=-1.5\\\\The\ line\ passes\ through\ the\ point\ (-1.5,0).$

The correct graph is attached.

6 0

3 years ago

Rylan is calculating the standard deviation of a data set that has 9 values. He determines that the sum of the squared deviation

stepladder [879]

The formula for the sum of the squares of the deviations is
SS = s² (N -1)

We are given
SS = 316
N = 9

Substituting
316 = s² (9 - 1)
Solving for s
s = 6.28

The standard deviation is 6.28

6 0

3 years ago

Read 2 more answers

Which answer choice is equivalent to the expression below?

anyanavicka [17]

In order to know the equivalent expression of the given above, all we need to do is to simplify it. So, for the exponents, what we need to do is just subtract.
The final answer would be 3/2xy^3. So the answer is option C. Hope this is the answer that you are looking for.

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3 years ago

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A person drilled a hole in a die and filled it with a lead weight, then proceeded to roll it 200 times. Here are the observed f

Alona [7]

Solution :

The objective of the study is to test the claim that the loaded die behaves at a different way than a fair die.

Null hypothesis, $H_0:p_1=p_1=p_3=p_4=p_5=p_6=\frac{1}{6}$

That is the loaded die behaves as a fair die.

Alternative hypothesis, $H_a$ : loaded die behave differently than the fair die.

Number of attempts , n = 200

Expected frequency, $E_i=np_i$

$=200 \times \frac{1}{6} = 33.333$

Test statistics, $x^2= \sum^6_{i=1} \frac{(O_i-E_i)^2}{E_i}$

$=\frac{(28-33.333)^2}{33.333}+\frac{(29-33.333)^2}{33.333}+\frac{(40-33.333)^2}{33.333}+\frac{(41-33.333)^2}{33.333}+\frac{(28-33.333)^2}{33.333}+$ $\frac{(34-33.333)^2}{33.333}$