Answer:

Step-by-step explanation:

y-intercept:

x-intercept:

The correct graph is attached.
The formula for the sum of the squares of the deviations is
SS = s² (N -1)
We are given
SS = 316
N = 9
Substituting
316 = s² (9 - 1)
Solving for s
s = 6.28
The standard deviation is 6.28
In order to know the equivalent expression of the given above, all we need to do is to simplify it. So, for the exponents, what we need to do is just subtract.
The final answer would be 3/2xy^3. So the answer is option C. Hope this is the answer that you are looking for.
Solution :
The objective of the study is to test the claim that the loaded die behaves at a different way than a fair die.
Null hypothesis, 
That is the loaded die behaves as a fair die.
Alternative hypothesis,
: loaded die behave differently than the fair die.
Number of attempts , n = 200
Expected frequency, 

Test statistics, 


≈ 5.8
Degrees of freedom, df = n - 1
= 6 - 1
= 5
Level of significance, α = 0.10
At α = 0.10 with df = 5, the critical value from the chi square table

= 9.236
Thus the critical value is 
![$P \text{ value} = P[x^2_{df} \geq x^2]$](https://tex.z-dn.net/?f=%24P%20%5Ctext%7B%20value%7D%20%3D%20P%5Bx%5E2_%7Bdf%7D%20%5Cgeq%20x%5E2%5D%24)
![$=P[x^2_5\geq 5.80]$](https://tex.z-dn.net/?f=%24%3DP%5Bx%5E2_5%5Cgeq%205.80%5D%24)
= chi dist (5.80, 5)
= 0.3262
Decision : The value of test statistics 5.80 is not greater than the critical value 9.236, thus fail to reject
at 10% LOS.
Conclusion : There is no enough evidence to support the claim that the loaded die behave in a different than a fair die.
Answer:

Step-by-step explanation:
Given, 
Take -8 factor common,

which can be written as

Add and subtract by 16 inside bracket,




