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3 years ago

Asap please! The triangles shown below must be congruent. 47 62 71

Mathematics

2 answers:

BaLLatris [955]3 years ago

7 0

These are congruent because they have all the same numbers except in different orders. Therefore your answer is true

sergejj [24]3 years ago

5 0

Answer:

its false

Step-by-step explanation:

i promise you

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HELP PLEASE AND NO LINKS!!

Alinara [238K]

Answer: 112

Step-by-step explanation:

educated guess

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2 years ago

Please help meh asap with this math problem

Ymorist [56]

Answer:

B: -a > -b

Step-by-step explanation:

a = 1, -a = -1

b = 3, -a = -3

-1 > -3

Therefore, -a > -b

6 0

2 years ago

Prove <2 and <7 are supplementary. Line L is parallel to line m

astraxan [27]

When both are added together they equal 180

7 0

2 years ago

Read 2 more answers

(Will try to mark brainliest)Use similar triangles to determine the equation of the line with a slope of 1/2 that passes through

Damm [24]

Answer:

Step-by-step explanation

Use similar triangles to determine the equation of the line with a slope of 1/2 that passes through the point (0, 2).

y − 2

What is the equation of the line in slope-intercept form?

✔ y = (1/2)x + 2

3 0

3 years ago

Use the compound interest formulas A= P (1 + r/n) ^nt and A= Pe ^ rt to solve the problem given. Round to the nearest cent. Find

Dennis_Churaev [7]

Answer:

$\$30,460$
$\$30,497$
$\$30,522$
$\$30,535$

Step-by-step explanation:

We know that,

$A=P\left (1+\dfrac{r}{n}\right )^{n\cdot t}$

where,

A = Amount after time t,

P = Principle amount,

r = Rate of interest,

n = Number of times interest is compounded per year,

t = time period in year.

Investment of $25,000 for 4 years at an interest rate of 5% if the money is compounded semiannually

Here,

P = $25,000

r = 5% = 0.05

n = 2 (as compounded semiannually)

t = 4 years

Putting the values,

$A=25000\left (1+\dfrac{0.05}{2}\right )^{2\times 4}$

$=25000\left (1+0.025\right )^{8}$

$=25000\left (1.025\right )^{8}$

$=\$30,460$

Investment of $25,000 for 4 years at an interest rate of 5% if the money is compounded quarterly.

Here,

P = $25,000

r = 5% = 0.05

n = 4 (as compounded quarterly)

t = 4 years

Putting the values,

$A=25000\left (1+\dfrac{0.05}{4}\right )^{4\times 4}$

$=25000\left (1+0.0125\right )^{16}$

$=25000\left (1.0125\right )^{8}$

$=\$30,497$

Investment of $25,000 for 4 years at an interest rate of 5% if the money is compounded monthly.

Here,

P = $25,000

r = 5% = 0.05

n = 12 (as compounded monthly)

t = 4 years

Putting the values,

$A=25000\left (1+\dfrac{0.05}{12}\right )^{12\times 4}$

$A=25000\left (1+\dfrac{0.05}{12}\right )^{48}$

$=\$30,522$

Investment of $25,000 for 4 years at an interest rate of 5% if the money is compounded continuously.

$A= Pe^{rt}$

where,

A = Amount after time t,

P = Principle amount,

r = Rate of interest,

t = time period in year.

Putting all the values,

$A= 25000e^{0.05\times 4}=\$30,535$

It can be observed that, the frequent we compound the amount, the more we get.

7 0

2 years ago