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ioda
3 years ago
12

If photocopier is purchased for $6,200 and depreciates in value by 15% per year. Which equation best describes the value of the

photocopier in t years?
Mathematics
1 answer:
77julia77 [94]3 years ago
7 0

Answer:

6,200(1-.15)^t

Step-by-step explanation:

P is the 6, 200 dollars and 1-.15% or. 85 % is how much it depreciates each year. And t is the time.

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3 years ago
Round to the nearest ten
Kitty [74]
The answer is A I hope this helps
7 0
3 years ago
Read 2 more answers
Convert the decimal to a fraction in simplest form:
Shkiper50 [21]

Answer:

Decimal 0.333 to a fraction in simplest form is:   \frac{333}{1000}

Step-by-step explanation:

Given the decimal

0.333

Multiply and divide by 10 for every number after the decimal point.

There are three digits to the right of the decimal point, therefore multiply and divide by 1000.

Thus,

0.333=\frac{0.333\cdot \:\:1000}{1000}

         =\frac{333}{1000}         ∵ 0.333×1000 = 333

Let us check if we can reduce the fraction \frac{333}{1000}

For this, we need to find a common factor of 333 and 1000 in order to cancel it out.

But, first, we need to find the Greatest Common Divisor (GCD) of 333, 1000

<u>Greatest Common Divisor (GCD) : </u>

The GCD of a, b is the largest positive number that divides both a and b without a remainder.

Prime Factorization of 333:      3 · 3 · 37

Prime Factorization of 1000:      2 · 2 · 2 · 5 · 5 · 5

As there is no common factor for 333 and 1000, therefore, the GCD is 1.

Important Tip:

  • As GCD is 1, therefore the fraction can not be simplified.

Therefore, decimal 0.333 to a fraction in simplest form is:   \frac{333}{1000}

4 0
3 years ago
Check that 2b+b and 3b have the same value when b is 1,2, and 3. Do 2b+b and 3b have the same value for all values of b? Explain
Inessa [10]

Answer:

Expression 2b+b and 3b have same values for all values of b.

Step-by-step explanation:

Given the two expression 2b+b and 3b and values of b as 1, 2 and 3.

Consider first expression that is, 2b+b.

Substituting the value of b=1,

2\left(1\right)+\left(1\right)=2+1=3 ....1

Substituting the value of b=2,

2\left(2\right)+\left(2\right)=4+2=6 ....2

Substituting the value of b=3,

2\left(3\right)+\left(3\right)=6+3=9 ....3

Consider second expression that is, 3b.

Substituting the value of b=1,

3\left(1\right)=3 ....4

Substituting the value of b=2,

3\left(2\right)=6 ....5

Substituting the value of b=3,

3\left(3\right)=9 ....6

For value of b=1, equation 1 and equation 4 are same, for value of b=2, equation 2 and equation 5 are same and for value of b=3 equation 3 and equation 6 are same.

Therefore both expression are same for all values of b.

3 0
3 years ago
How to solve these equations
nlexa [21]
All u have to do is plug in the values
68) -(4q) = -(4*-3) =-4*3= -12
70) 5P-6= (5*5)-6 =25-6= 19
72) 7q-7p= 7(-3)-7(5) = -21-35= -56
74)2q/(4p) = 2(-3)/4(5)= -6/20= -3/10
6 0
3 years ago
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